Answer:
4x² -4xy -4y -4
Step-by-step explanation:
In this case, a= 2x -y and b= y +2.
(2x -y)² -(y +2)²
= (2x -y +y +2)[2x -y -(y +2)]
= (2x +2)(2x -y -y -2)
= (2x +2)(2x -2y -2)
= 2x(2x) +2x(-2y) +2x(-2) +2(2x) +2(-2y) +2(-2) <em>(expand)</em>
= 4x² -4xy -4x +4x -4y -4
= 4x² -4xy -4y -4
Alternatively, start by expanding the brackets.
(2x -y)² -(y +2)²
= 4x² -4xy +y² -(y² +4y +4)
= 4x² -4xy +y² -y² -4y -4 <em>(</em><em>expand</em><em>)</em>
= 4x² -4xy -4y -4 <em>(</em><em>simplify</em><em>)</em>
All you've got to do is some simple algebra! When you solve for a variable, you are trying to get it alone on one side of the equation. So, we want something that looks like y = ...
First, add 21x to both sides of the equation. This will cancel out the -21x on the left side.
-21x + 3y = 6
-21x + 3y + 21x = 6 + 21x
3y = 21x + 6
Now, to get y alone, divide both sides of the equation by 3. This will cancel out the coefficient of 3 on the left side.
3y = 21x + 6
(3y)/3 = (21x + 6)/3
y = 7x + 2
There's the answer. Hope that helps! :)
<h3><em>(HCF)=(36,60,84)</em></h3><h3><em>Factors of 36
</em></h3><h3><em>
</em></h3><h3><em>List of positive integer factors of 36 that divides 36 without a remainder.
</em></h3><h3><em>
</em></h3><h3><em>1,2,3,4,6,9,12,18,36</em></h3><h3>Factors of 60
</h3><h3>
</h3><h3>List of positive integer factors of 60 that divides 60 without a remainder.
</h3><h3>
</h3><h3>1,2,3,4,5,6,10,12,15,20,30,60</h3><h3>Factors of 84
</h3><h3>
</h3><h3>List of positive integer factors of 84 that divides 84 without a remainder.
</h3><h3>
</h3><h3>1,2,3,4,6,7,12,14,21,28,42,84</h3><h3 /><h3>We found the factors 36,60,84 . The biggest common factor number is the HCF number.
</h3><h3>So the highest common factor 36,60,84 is 12.</h3><h3><em>HOPE IT HELPS....</em></h3>
Answer:
Step-by-step explanation:
The odd numbers.
Suppose you have 31 and 27 when you add these two together, you get 58 which is not an odd number.
If you need a more mathematical proof, you could do it this way.
2x+1
2x is even. Anything multiplied by 2 is even. When you add 1 you get an odd number
So continue on
2y + 1 is the other number.
2x + 1 + 2y + 1 = 2(x + y) + 2
2 (x + y ) is even. When you add 2 to it, nothing changes. The result is still even.
Put x = 2 in f(x) you'll get,f(2) = 2(3) x 2 = 12. so next point could be ( 2,12)
