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3 years ago

Find the product of (x-7) squared.

Mathematics

1 answer:

laiz [17]3 years ago

6 0

The product is X^2-49.

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Find the length of "a", to<br> the nearest tenth, using<br> the Pythagorean Theorem.<br> Enter

bearhunter [10]

Answer:

$\sqrt{28} \approx 5.3$

Step-by-step explanation:

The Pythagorean Theorem says if you have a right triangle, then relationship between the three sides is the sum of the square of each leg is the hypotenuse squared.

So $a^2+b^2=c^2$

where a and b are legs and c is the hypotenuse.

Plug in your a,b, and c. In this case it is a,6, and 8.

This means we have

$a^2+6^2=8^2$

Simplify where you can before we begin the solving (the moving around of things to other sides).

$a^2+36=64$

Now time for the solving. We are first going to get $a^2$ by itself.

To do this, we just need to subtract 36 on both sides giving us:

$a^2=64-36$

$a^2=28$

Now to get rid of the square on a, just square root both sides:

$a=\sqrt{28}$ .

8 0

3 years ago

I need help asap !!!!!!

OLEGan [10]

Answer:

B. ZJ = 85

C. KH = 68

Step-by-step explanation:

Given that ZK, ZL, ZM are perpendicular bisectors of ∆GHJ, they form a circumcenter which is equidistant from the vertices of ∆GHJ. According to the circumcenter theorem, ZH = ZG = ZJ = 85.

Also each median formed is equal. This means: KH = GH, LH = LJ, MG = MJ

Since HG = 136, KH = ½ of 136 = 68.

The two options that are true are:

B. ZJ = 85

C. KH = 68

4 0

3 years ago

Using the order of operations, what should be done first to evaluate 12 divided by (negative 6) (3) + (negative 2)? Divide 12 by

koban [17]

12 / (-6)(3) + (-2)

First divide 12 by -6

3 0