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True [87]
3 years ago
11

PLEASE HELP !!!!!!! WILL MARK BRAINLIEST FOR A REAL ANSWER

Mathematics
1 answer:
rjkz [21]3 years ago
3 0

Answer:

A. Find the maximum height of the acrobat.

Step-by-step explanation:

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60<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B60%7D%7B108%3F%7D%20" id="TexFormula1" title=" \frac{60}{108?} " alt=" \fra
Phantasy [73]

I guess you want to simplify this:-

60 / 108   = 30/54      (dividing top and bottom by 2)

= 15/27   ( divide by 2 again)

= 5/9   Answer    (dividing   top and bottom by 3)

6 0
3 years ago
Read 2 more answers
The soccer net in Peter's back yard is 5 1/2 feet high, but only 4 feet wide. Jill's soccer net is also 5 1/2 feet high, but is
Black_prince [1.1K]

The area of Jill's soccer net is 3 times larger than area of Peter's soccer net.

<h3> Area of Peter's soccer net</h3>

The area of Peter's soccer net is determined by using area of rectangle as shown below;

A1 = 5.5 ft x 4 ft

A1 = 22 ft²

<h3> Area of Jill's soccer net</h3>

A2 = 5.5 ft x 12 ft

A2 = 66 ft²

<h3>Ratio of the area of their soccer net</h3>

A2/A1 = 66/22

A2/A1 = 3

Thus, the area of Jill's soccer net is 3 times larger than area of Peter's soccer net.

Learn more about area of rectangle here: brainly.com/question/25292087

4 0
2 years ago
CAN SOMEONE PLEASE HELP I WILL GIVE 50 POINTS
Alex777 [14]

Answer:

What do you need help with?

Step-by-step explanation:

6 0
3 years ago
The interior angles of a triangle have measures (2x -5) degrees , (4x -1) degrees , and 30 degrees
N76 [4]
Umm... I really dont get maths in my brain. Dont mind me though :P . 
but i can sure tell u a little i know .
4x-1+2x-5+30=180 (sum of interior angles of triangle)
or, 6x+24=180
or, 6x=156
therefore, X=26 degrees
thankyou :D

5 0
3 years ago
Which is an incorrect rounding for 53.845? I'm trying to do the I-Ready diagnostic and I'm try my best to pass is can you help m
ivolga24 [154]
53.9 is incorrect rounding. This is because the 4 in the 100’s place is below 5. The correct rounding would be 53.85
7 0
3 years ago
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