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VLD [36.1K]
3 years ago
12

5. Micheal has $750 to deposit into no different accounts.

Mathematics
1 answer:
vredina [299]3 years ago
5 0

I=prt

I= 400×(4.5/100)×5

I=$90

total 400+90=$490

I=prt

I=250×(2/100)×5

I=$25

total 250+25=$275

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Jamie says that if she knows only the measure of one angle in an isosceles triangle, she can always determine the measures of th
lozanna [386]

Answer:

Jamie is correct

Step-by-step explanation:

Jamie is correct.

Example: isosceles triangle ABC AB=AC

∠B = ∠C        ∠A + ∠B + ∠C = 180°

if ∠A = x     ∠B = ∠C = 1/2 * ( 180° - x)

if ∠B or ∠C = x            ∠A = 180° - 2x

6 0
3 years ago
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Washington elementary has 4,358 students.jefferson high schol has 3 times as many students as washington elementary.about how mn
schepotkina [342]
Jefferson High School has a population of 13,074.

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3 years ago
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The total cost of attending a basketball game includes the price of a ticket (parking included). An individual ticket costs $12.
IrinaK [193]

Answer:

12n+34

n represents each ticket and 34 is parking lot

5 0
3 years ago
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
PLS HELP!! need the answer asap
julsineya [31]
The answer would be C) P,D and A
4 0
3 years ago
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