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2 years ago

(2x-3)(x+2)-(3-2x)(3x-2)=0

Mathematics

2 answers:

garik1379 [7]2 years ago

7 0

(2x-3)(x+2)-(3-2x)(3x-2)=0

(2x²+4x-3x-6) - (9x-6-6x²+4x)=0

(2x²+4x-3x-6) + (6x²-4x-9x+6)=0

(2x²+x-6)+(6x²-13x+6)=0

8x²-12x=0

Step2247 [10]2 years ago

3 0

Answer:

the answer is X = 0.75

Step-by-step explanation:

you just need to simplify everything in the brackets and calculate

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3 years ago

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3 years ago

Consider the system of equations.

Harman [31]

The solution to the system of equations x + 2y = 1 and -3x-2y = 5 is:

x = -3, y = 2

The given system of equations:

x + 2y = 1............(1)

-3x - 2y = 5..........(2)

This can be written in matrix form as shown:

$\left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Find the determinant of $\left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right]$

$\triangle = 1(-2) - 2(-3)\\\triangle = -2+6\\\triangle = 4$

$\triangle_x = \left[\begin{array}{ccc}1&2\\5&-2\end{array}\right]\\\triangle_x = 1(-2)-2(5)\\\triangle_x = -2-10\\\triangle_x =-12$

$\triangle_y = \left[\begin{array}{ccc}1&1\\-3&5\end{array}\right]\\\triangle_y = 1(5)-1(-3)\\\triangle_y = 5 + 3\\\triangle_y =8$

$x = \frac{\triangle_x}{\triangle} \\x = \frac{-12}{4} \\x = -3$

$y = \frac{\triangle_y}{\triangle} \\y = \frac{8}{4} \\y = 2$

The solution to the system of equations x + 2y = 1 and -3x-2y = 5 is:

x = -3, y = 2

Learn more here: brainly.com/question/4428059

3 0

2 years ago

X(x-y) - y( x- y) simplify

Rudik [331]

Step-by-step explanation:

x²-xy-xy+y²

x²+2xy+y²

hope it helps

3 0

3 years ago