Please help i will give brainiest!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Lorico [155]3 years ago

4 0

Answer:

Part A: Two pieces of information that are provided by the graph is the median which is 55 and the range which is 20-95. Two piece of information that is not provided by the graph is the mean and mode.

Part B: The interquartile range of the data is 25. It represent the range between the amount of time in minutes that the students of a class surfed the internet.

I am not sure if this is all correct, but i tired. I hope this helps :)

FrozenT [24]3 years ago

3 0

Answer:

Part A: 2 pieces of information that are provided by the graph would be the median (median=55) and the range (which is 20-95) The 2 pieces of information that aren't provided by the graph are the mean and mode.

Part B: The IQR of the data is 25. It is the range between the amount of time in minutes that the students of a class surfed the internet.

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Data on tuition and mid-career salary are collected from a number of universities and colleges. The result of the data collectio

alexira [117]

Answer:

1. annual tuition 2. $-27139 3. slope = -0.91

Step-by-step explanation:

1. An independent variable is the factor that is not determined by the model in this case the annual tuition variable (the linear regression model factor)

2. substitute $30,000 into the linear regressions equation gives:

y = -0.91(30000) + 161 = -27139

This value tells us that when the annual tuition is $30,000 the average mid-career salary of graduates is predicted to be -$27,139

3. the slope if the regression is represented by the coefficient of the factor in the linear regression model. In this case, as the factor is x or the annual tuition, and the coefficient of this variable in the given example is -0.91 which in turn is the slope of the model.

8 0

4 years ago

Help on math plz <br>15 and 16 explain

Anit [1.1K]

For 15:
equate both left-hand sides and you will get a quadratic ..

Solve it for x, you get:

x=4, x=-1.75

B

For 16:
the vertex would be (h,k) = (2,4)

A