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wolverine [178]
3 years ago
5

Points J, K, L, and M are midpoints of the sides of the rectangle EFGH. Prove that quadrilateral JKLM is a rhombus by finding th

e lengths of the sides. The diagram is not drawn to scale.

Mathematics
1 answer:
GaryK [48]3 years ago
6 0
Distance from J to F = b
D from F to K = a
a^2+b^2=JK^2

D from K to G = a
D from G to L = b
a^2+b^2=KL^2

D from L to H = b
D from H to M = a
a^2+b^2=LM^2

D from M to E = a
D from E to J = b
a^2+b^2=MJ^2

For each side, I used the Pythagorean theorem (a^2+b^2=c^2) to find the length. Since every side of the quadrilateral squared (aka to the power of two) equals a^2+b^2, every side squared equals each other. So JK^2=KL^2=LM^2=MJ^2. If you take the square root of each side of the equal signs, you’re left with JK=KL=LM=MJ. In order for a quadrilateral to be a rhombus, each side must be equivalent. Each side in this quadrilateral is equivalent, therefore it is a rhombus.
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Answer:

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Step-by-step explanation:

From the chart,

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The total number of one centimeter lines in the first n diagrams is given by the expression 

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When n = 2

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= > x² + 7x + 12 = 12

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