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lozanna [386]
3 years ago
7

I need help pls no wronge answers this is for a test

Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

I think the answer is

Step-by-step explanation:

(D) OR (B)

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Write mixed number for p so that 3 1/4 × p is more than 3 1/4
Sholpan [36]

Answer:

1 3/5

Step-by-step explanation:

Anything larger than 1 multiplied by 3 1/4 would result in a number more than 3 1/4.

8 0
3 years ago
Silas and Lilly attended a math conference. The total registration fee was $327.50. If each person paid the same amount, which e
castortr0y [4]

Answer:I think the answer is letter B.

Step-by-step explanation:

8 0
3 years ago
Please answer these and I will give brainliest!!!
ollegr [7]

Answer:

#1. 1232 feet per minute

#2. $14.81 per second

#3. 46.93 feet per second

Hope This Helps!

And that it's right!

4 0
3 years ago
Andre has a summer job selling magazine subscriptions. He earns $25 each week plus $3 for every subscription he sells. Andre hop
Strike441 [17]

Answer: 25 + 3n

Step-by-step explanation:

Hi, the answer is lacking the last part:

<em>Write an expression for the amount of money he makes this week. </em>

So, to answer this we have to write an expression:

The fixed amount that he earns per week (25) plus the product of the amount he earns per subscription (3) and the number of subscriptions sold (n) , must be equal to his weekly earnings.

Mathematically speaking:

25 + 3n

Feel free to ask for more if needed or if you did not understand something.  

7 0
3 years ago
WILL GIVE BRAINLIEST
stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph.  A cargo plane left sometime later flying in the same direction at an average speed of 207 mph.  After flying for 5.3 hours the cargo plane caught up with the Air Force plane.  

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, \text { distance travelled }=\text { speed } \times \text { time }

For air force plane \rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }

\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, 159 \times \text { time taken by air force plane }=207 \times 5.3

\Rightarrow =\frac{207 \times 5.3}{159}

\Rightarrow =\frac{1097.1}{159}

Time taken by air force plane = 6.9  hrs

6 0
3 years ago
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