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VARVARA [1.3K]
3 years ago
7

JoAnn works in a publicity office at the state university. She is paid $13.50 an hour for the first 35 hours she works each week

and $20.25 an hour for every hour after that. If she makes $675.00 one week, how many hours did she work?
Mathematics
2 answers:
Yanka [14]3 years ago
4 0

Answer:

44 hours

Step-by-step explanation:

13.50 × 35 = 472.5

675 - 472.5 = 184.5

184.5 ÷ 20.25 = 9.1

9.1 + 35 = 44.1

rounded to 44

natali 33 [55]3 years ago
4 0

Answer:

JoAnn worked for the week = 45 hours

Step-by-step explanation:

JoAnn paid $13.50 an hour for the first 35 hours each week.

$20.25 each hour after 35 hours.

The equation is

35*13.50 +20.25x = 675, where "x" represents the number of hours she worked after 35 hours.

472.50 + 20.25x = 675

20.25x = 675 - 472.50

20.25x = 202.50

x = 202.50/20.25

x = 10

JoAnn worked for the week = 35 + 10 hours

JoAnn worked for the week = 45 hours.

That's the answer.

Hope you will understand the concept.

Thank you.

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Answer:

35.w/g=m

36. P=1/2Q-15

37. R=IV

38. b=-mx+y

39. a) t=-d-e+f

     b) t=19.175

40. No, X=-2.4

Step-by-step explanation:

Explanation for 40:

2(x-4)-4x=-6x+9x+4

first do the parentheses

2x-8-4x=-6x+9x+4

next combine like terms

-2x-8=3x+4

add 2x to each side

-8=5x+4

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7 0
2 years ago
Which function does f(-1/2) ≠ -1
snow_lady [41]

Answer:

anything but 2

Step-by-step explanation:

f(-1/2)

If you plug in 2, you'd get -1. But if you plug in other values, it won't be equal to -1.

6 0
2 years ago
The following are scores for students in Ms. Kennedy's math class.What is the range of the scores?
Eddi Din [679]

Answer:

The answer will be D. 181

Step-by-step explanation:

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1 year ago
A researcher wishes to estimate the average blood alcohol concentration​ (BAC) for drivers involved in fatal accidents who are f
Mnenie [13.5K]

Answer:

A 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

Step-by-step explanation:

We are given that a researcher randomly selects records from 60 such drivers in 2009 and determines the sample mean BAC to be 0.16 g/dL with a standard deviation of 0.080 ​g/dL.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~   t_n_-_1

where, \bar X = sample mean BAC = 0.16 g/dL

            s = sample standard deviation = 0.080 ​g/dL

            n = sample of drivers = 60

            \mu = population mean BAC in fatal crashes

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

So, a 90% confidence interval for the population mean, \mu is;

P(-1.672 < t_5_9 < 1.672) = 0.90  {As the critical value of t at 59 degrees of

                                              freedom are -1.672 & 1.672 with P = 5%}    P(-1.672 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.672) = 0.90

P( -1.672 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.672 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.672 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.672 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.672 \times {\frac{s}{\sqrt{n} } } , \bar X+1.672 \times {\frac{s}{\sqrt{n} } } ]

                                       = [ 0.16-1.672 \times {\frac{0.08}{\sqrt{60} } } , 0.16+1.672 \times {\frac{0.08}{\sqrt{60} } } ]

                                       = [0.143, 0.177]

Therefore, a 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

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