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ioda
3 years ago
12

WILL GIVE BRAINLIEST

Mathematics
1 answer:
stira [4]3 years ago
6 0

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph.  A cargo plane left sometime later flying in the same direction at an average speed of 207 mph.  After flying for 5.3 hours the cargo plane caught up with the Air Force plane.  

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, \text { distance travelled }=\text { speed } \times \text { time }

For air force plane \rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }

\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, 159 \times \text { time taken by air force plane }=207 \times 5.3

\Rightarrow =\frac{207 \times 5.3}{159}

\Rightarrow =\frac{1097.1}{159}

Time taken by air force plane = 6.9  hrs

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3 years ago
Mr. Gonzazales has only 42.50 to spend he wants to buy 29 t shirts including tax and some bracelets that cost 4.50 each includin
erica [24]

Answer:

He can buy <u>3 bracelets</u>.

Step-by-step explanation:

Given:

Mr. Gonzales has only 42.50 to spend he wants to buy 29 t shirts including tax and some bracelets that cost 4.50 each including tax.

Now, to find the number of bracelets he can buy.

Let the number of bracelets he can buy be x.

Price of each bracelets = 4.50.

Total amount to spend = 42.50.

Number of t-shirts = 29.

Now, to get the number of bracelets we put an equation:

29+4.50\times x=42.50\\\\29+4.50x=42.50

<em>Subtracting both sides by 29 we get:</em>

<em />4.50x=42.50-29\\\\4.50x=13.5<em />

<em>Dividing both sides by 4.50 we get:</em>

x=3.

<u>The number of bracelets = 3.</u>

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6 0
4 years ago
If events A and B are independent, what must be true?A.) P(AB) = P(B)
anygoal [31]

Answer:

B.) P(A/B) = P(A)

Step-by-step explanation:

If two events, A and B are independent:

We have that:

P(A \cap B) = P(A)P(B)

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

Since they are independent:

P(A \cap B) = P(A)P(B)

Then

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{P(A)P(B)}{P(A)} = P(B)

So

P(B|A) = P(B), or either:

P(A|B) = P(A), and thus, the correct answer is given by option B.

7 0
3 years ago
Can someone give me tips for flying on an airplane? ✈️ ​
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The parallelogram has the angle measures shown. Can you conclude that it is a rhombus, a
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