First, you need to determine the possible side lengths of your third side. Here, your third side can be your hypotenuse or another side length. If it is your hypotenuse, it will be equal to sqrt(8^2+5^2)=sqrt(64+25)=sqrt(89). If it is your side length, it will be equal to sqrt(8^2-5^2)=sqrt(64-25)=sqrt(39). You can find the difference by subtracting these from each other in a calculator, making your difference equal to sqrt(89)-sqrt(39)≈3.2 inches.
9745152 ÷ 61 = 159756.590164
Comment if you need any more help :)
A^2+b^2=c^2
20^2+b^2=29^2
400+b^2=841
-400. -400
b^2=√441
b=21
The sum of the squares of their ages is; 5x²
<h3>How to Solve Algebraic Word Problems?</h3>
We are told that Maria is twice the age of Miriam.
Now, of the age of Miriam is x, then we can say that;
Age of Mariam = x
Age of Maria = 2x
Now, we want to find the sum of the squares of their ages. Thus, this is expressed as;
x² + (2x)²
= x² + 4x²
= 5x²
Read more about Algebraic Word Problems at; brainly.com/question/13818690
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The complete question is;
Express in algebraic language: the sum of the squares of the ages of Maria and Miriam, if it is known that Maria is twice the age of Miriam.
Answer: C.
Step-by-step explanation: Plug in x in the formula. Solve for each y by plugging in each x in the formula and seeing if it works. This took me like 3 min to solve
