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1 year ago

Eighth grade > V.4 Area and circumference of circles CHV

Mathematics

1 answer:

kati45 [8]1 year ago

8 0

Answer: $D=13.8$

Step-by-step explanation:

To fing the diameter of a circle when given the circumfrence we use the formula of

$D=\frac{c}{\pi }$

$D= \frac{43.332}{3.14}$

$D=13.8$

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A²b-b²<br> if a = 3 and b = -4

LiRa [457]

The answer is -52

First you must substitute the variables

$(3^2)(-4)-(-4^2)$

Then you must simplify

$-52$

8 0

2 years ago

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liq [111]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Please help me answer this for me please

slamgirl [31]

Answer:

first one is 5.8

second on is 4.47 round

third one is 1.92

Step-by-step explanation:

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2 years ago

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

2 years ago

Which pair of equations below is a result of constructing the altitude, h, in traingle ABC?

Korolek [52]

Answer:

sinA = h/c; sinC = h/a

Step-by-step explanation:

Which pair of equations below is a result of constructing the altitude, h, in Triangle ABC?

sinA= h/c

sinC= h/a

sinA= h/c

sinB= b/c

sinA= b/c

sinC= b/a

Solution:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as right angled, acute, obtuse and isosceles triangle.

In right angle triangle, one angle is 90°. From Pythagoras theorem, the square of the longest side (hypotenuse) is equal to the sum of the square of the two sides.

In right triangle, trigonometric identities are used to show the relationship between the sides of a triangle and the angles.

sinθ = opposite / hypotenuse, cosθ = adjacent / hypotenuse, tanθ = opposite / adjacent

Therefore in triangle ABC:

sinA = h/c; sinC = h/a

4 0

2 years ago