Answer:
x1, x2 = 7.73 , 4.27
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 12x + 33
a = 1 b = -12 c = 33
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (12 + √(-12^2 - (4 * 1 * 33))) / 2 * 1
x1 = (12 + √(144 - 132)) / 2
x1 = (12 + √12) / 2
x1 = (12 + 3.46) / 2
x1 = 15.46 / 2
x1 = 7.73
x2 = (12 - √(-12^2 - (4 * 1 * 33))) / 2 * 1
x2 = (12 - √(144 - 132)) / 2
x2 = (12 - √12) / 2
x2 = (12 - 3.46) / 2
x2 = 8.54 / 2
x2 = 4.27
Answer is in the file below
tinyurl.com/wpazsebu
Answer:
1, 5, 17, 53, 161
Step-by-step explanation:
Given:
First five terms of the sequence:
35 + 52 + 3(x + 2) = 180
87 + 3x + 6 = 180 ( add the like terms and use distributive property)
93 + 3x = 180
-93 -93
3x = 87
÷3 ÷3
x = 29
( the sum of all triangle angles is 180)
General formula for circles at the origin is x^2+y^2=R^2 where R is the radius.So R^2=4225. Solve for R.
