All categories

3 years ago

The area of a rectangle is 28square miles. The length is 7 miles.

1 answer:

6 0

Area=length times width
area=28
length=7

28=7 times width
divide both sides by 7
4=width

the width is 4 miles
and perimiter is 22mi

You might be interested in

(x+3)(x-5)=(x+3)(x−5)=

s344n2d4d5 [400]

Answer:

(x+3)(x-5)=(x+3)(x-5)

x^2-2 = x^2-2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Help me with this. i am not smart ..

marta [7]

I’m not that smart... but let me use first as example.. 240 divided by 4

3 0

3 years ago

Read 2 more answers

Can someone help me with this question plz thx :,)

Alenkinab [10]

Answer:

43.35

Step-by-step explanation:

3 0

2 years ago

An oak tree cast a shadow of 14 feet. A 30 foot flagpole casts a shadow of 60 how tall the Oak tree?

Alina [70]

Answer:

7 feet

Step-by-step explanation:

Oak tree = x

14 : x as 60 : 30

Simplify the right ratio

14 : x as 2:1

Get the same first number in both ratios by multiplying 2:1 by 7

14 : x as 2(7) + 1(7)

14 : x as 14 : 7

Since the first number in each ratio is the same, we know that that x and 7 are equal

x = 7

Hope this helps, feel free to let me know if you would like a further explanation :)

5 0

3 years ago

is picking out some movies to rent, and he has narrowed down his selections to 5 documentaries, 7 comedies, 4 mysteries, and 5 h

pogonyaev

Answer: 91

Step-by-step explanation:

Given : The number of documentaries = 5

The number of comedies = 7

The number of mysteries = 4

The number of horror films =5

The total number of movies other than comedy = 14

Now, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is given by :-

$^7C_7\times^{14}C_2\\\\\dfrac{7!}{7!(7-7)!}\times\dfrac{14!}{2!(14-2)!}\\\\=(1)\times\dfrac{14\times13}{2}\\\\=91$

Therefore, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is 91 .

5 0

3 years ago