THE NUCLEUS, BECAUSE FIRST OF THE NUCLEUS CONTROLS MOST OF THE HEREDITARY INFORMATION OF DNA YOU KNOW WHAT IS RIGHT? (DEOXYRIBONUCLEIC ACID) WHICH IS FOUND ON THE CHROMOSOMES. ALL THE OTHER ORGANELLES THAT DOES THERE OWN FUNCTIONS ARE CONTROLLED BY THE NUCLEUS. FOR EXAMPLE:
NUCLEUS: HEY RIBOSOMES!!
RIBOSOMES: YEA BOSS?
NUCLEUS: GO TO THE ENDOPLASMIC RECTULUM AND PRODUCE PROTEINS THERE
RIBOSOMES: YOU GOT IT BOSS!
SEE.... RIBOSOMES PRODUCE PROTEINS FOLLOWING CODED INSTRUCTIONS THAT COME FROM THE NUCLEUS. "THE CONTROL CENTER"
Heart rate is controlled by the two branches of the autonomic (involuntary) nervous system. The sympathetic nervous system (SNS) and the parasympathetic nervous system (PNS). The sympathetic nervous system (SNS) releases the hormones (catecholamines - epinephrine and norepinephrine) to accelerate the heart rate. The parasympathetic nervous system (PNS) releases the hormone acetylcholine to slow the heart rate. Such factors as stress, caffeine, and excitement may temporarily accelerate your heart rate, while meditating or taking slow, deep breaths may help to slow your heart rate.
The 5 ounces of beef strip steak would count as 5-ounce equivalents in the Protein Foods Group.
Al the foods made from poultry, meat, seafood, peas and beans, eggs, processed soy products, seeds, and nuts are regarded as the component of the Protein Foods Group.
Steak, like any other animal product, is a rich source of protein. A 5 oz serving of steak gives 38 grams of protein, more than 6 times of the amount in one egg. The proteins help in repairing muscles and other tissues and also helps in building muscles.
Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
Synchroniser switch is in the "on" position.
