Answer:
Each group will have 6 students, but there are less than 48 students in the class.
Now, if there are x teams, and each team has 6 students, the total number of students in teams will be x times 6, or:
x*6
And there are less than 48 students, then we x*6 will be smaller than 48, or:
x*6 < 48.
Now we can solve this inequality by dividing by 6 in both sides, this leads to:
x*6/6 < 48/6
x < 8
Then the total number of teams will be smaller than 8.
Answer:
False?
Step-by-step explanation:
The arrow keeps going may thats why its false
Answer is: A. 0.50 [x + (x + 0.25x)], B. 0.50 (x + 1.25x), E.0.50 (2.25x)
If AM=10, then AC=10 because both are radii. TC is a diameter so that’ll just be the radius doubled. TC=20!
Answer:
y = (x/(1-x))√(1-x²)
Step-by-step explanation:
The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:
x = r·cos(θ)
y = r·sin(θ)
x² +y² = r²
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r = sec(θ) -2cos(θ)
r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)
r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²
(x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations
x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor
y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)
![\boxed{y=\dfrac{x\sqrt{1-x^2}}{1-x}}](https://tex.z-dn.net/?f=%5Cboxed%7By%3D%5Cdfrac%7Bx%5Csqrt%7B1-x%5E2%7D%7D%7B1-x%7D%7D)
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The attached graph shows the equivalence of the polar and rectangular forms.