Answer:
Step-by-step explanation:
Alright, lets get started.
The total surface area of rectangular pyramid will be the area of all four faces and area of base.
The faces are triangular, so area will be = 
Area of face = 
Another face area = 
Each face has its similar another face. So total area of faces will be = 
Area of base = 
So total surface area = 
square feet
Hence the total surface area is 596 square feet. : Answer
Hope it will help :)
Answer:
Step-by-step explanation:
1 one 10 ten 100 hundred 1.000 one thousand 10,000 ten thousand 100,000 hundred thousand 1,000,000 One million 10,000,000 ten million 100,000,000 Hundred million 1,000,000,000 One billion 10,000,000,000 ten billion 100,000,000,000 hundred billion 1,000,000,000,000 one trillion etc.
Answer:
$9
Step-by-step explanation:
7.50/5= $1.5 an apple
6* 1.5 = $9 for 6 apples
Part A
Answer: The common ratio is -2
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Explanation:
To get the common ratio r, we divide any term by the previous one
One example:
r = common ratio
r = (second term)/(first term)
r = (-2)/(1)
r = -2
Another example:
r = common ratio
r = (third term)/(second term)
r = (4)/(-2)
r = -2
and we get the same common ratio every time
Side Note: each term is multiplied by -2 to get the next term
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Part B
Answer:
The rule for the sequence is
a(n) = (-2)^(n-1)
where n starts at n = 1
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Explanation:
Recall that any geometric sequence has the nth term
a(n) = a*(r)^(n-1)
where the 'a' on the right side is the first term and r is the common ratio
The first term given to use is a = 1 and the common ratio found in part A above was r = -2
So,
a(n) = a*(r)^(n-1)
a(n) = 1*(-2)^(n-1)
a(n) = (-2)^(n-1)
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Part C
Answer: The next three terms are 16, -32, 64
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Explanation:
We can simply multiply each previous term by -2 to get the next term. Do this three times to generate the next three terms
-8*(-2) = 16
16*(-2) = -32
-32*(-2) = 64
showing that the next three terms are 16, -32, and 64
An alternative is to use the formula found in part B
Plug in n = 5 to find the fifth term
a(n) = (-2)^(n-1)
a(5) = (-2)^(5-1)
a(5) = (-2)^(4)
a(5) = 16 .... which matches with what we got earlier
Then plug in n = 6
a(n) = (-2)^(n-1)
a(6) = (-2)^(6-1)
a(6) = (-2)^(5)
a(6) = -32 .... which matches with what we got earlier
Then plug in n = 7
a(n) = (-2)^(n-1)
a(7) = (-2)^(7-1)
a(7) = (-2)^(6)
a(7) = 64 .... which matches with what we got earlier
while the second method takes a bit more work, its handy for when you want to find terms beyond the given sequence (eg: the 28th term)
