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3 years ago

PLEASE HELP ME WITH THIS I WILL APPRECIATE IT :)

Mathematics

1 answer:

marta [7]3 years ago

8 0

Answer:

If Train A is heavier than Train B and Train B weights 334 and the difference is 240 ton.

then the equation youre using is

240=334-x

334+240=x

574=x

therefore, train a weights 574 ton

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Question is below (wasn't sure about the answer)

Paha777 [63]

Answer: Choice A)

$H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\$

=================================================

Work Shown:

$SA = 2(LW + LH + HW)\\\\2(LW + LH + HW) = SA\\\\LW + LH + HW = \frac{SA}{2}\\\\LH + HW = \frac{SA}{2} - LW\\\\H(L + W) = \frac{SA}{2} - LW\\\\H = \frac{\frac{SA}{2} - LW}{(L + W)}\\\\H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\$

This is not the only way to solve for H.

3 0

3 years ago

Please explain how to do this!

irakobra [83]

Ask ur mom she can knows

5 0

3 years ago

Which set of points represents a function?

Greeley [361]

Answer:

the 0,2 does beautiful as it comes

4 0

3 years ago

2x²-5x-12=0 (simplify solution set)

Arada [10]

Answer:

x = 4 or x = -3/2

Step-by-step explanation:

To simplify and solve this, let's use the quadratic formula.

So the format of a quadratic equation is supposed look like this:

$ax^2+bx+c=0$

Let's find a, b, c:

a is the coefficient of x^2
b is the coefficient of x
c is the constant term

Now let's solve the equation.

Let's solve your equation step-by-step.

2x^2−5x−12=0

For this equation: a=2, b=-5, c=-12

2x^2+−5x+−12=0

Step 1: Use quadratic formula with a=2, b=-5, c=-12.

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-12)} }{2(2)}$

$x=\frac{5\pm\sqrt{121} }{4}$

$x=4$ or $x=\frac{-3}{2}$

<u />

<u>Answer:</u>

x = 4 or x = -3/2

7 0

2 years ago

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

3 0

3 years ago