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hjlf
3 years ago
5

What is n in 3/5n + 15 =10+2/5n

Mathematics
2 answers:
Phantasy [73]3 years ago
8 0
Simplify both sides of the equation.

<span><span><span><span>3/5</span>n </span>+ 15 </span>= <span><span><span>2/5</span>n </span>+ 10


</span></span>Subtract 2/5n from both sides.

<span><span><span><span><span>3/5</span>n </span>+ 15 - </span><span><span>2/5</span>n </span></span>= <span><span><span><span>2/5</span>n </span>+ 10 - </span><span><span>2/5</span>n</span></span></span><span><span><span><span>15</span>n </span>+ 15 </span>= 10


</span>Subtract 15 from both sides.

<span><span><span><span><span>1/5</span>n </span>+ 15 - </span>15 </span>= <span>10 - 15</span></span><span><span><span>1/5</span>n </span>= -<span>5


</span></span>Multiply both sides by 5.

<span><span>5 </span></span>× (1/5n) = (5) × (−5)<span>n = -<span><span>25


Answer: n is -25.</span></span></span>
den301095 [7]3 years ago
7 0
The answer is n is -25
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A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.
AVprozaik [17]

Answer:

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Where \mu=61 and \sigma=14

Since the distribution for X is normal then the distribution for the sample mean  is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 61

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So then is appropiate use the normal distribution to find the probabilities for \bar X

Step-by-step explanation:

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Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(61,14)  

Where \mu=61 and \sigma=14

Since the distribution for X is normal then the distribution for the sample mean \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 61

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Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

\bar x = \frac{\sum_{i=1}^n X_i}{n}

And the population mean is given by:

\mu= \frac{\sum_{i=1}^n X_i}{N}

The population variance is defined by:

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And the sample variance is defined as:

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