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2 years ago

-21 – (-14) =+= Helpppp

Mathematics

1 answer:

Scorpion4ik [409]2 years ago

3 0

Answer:

-21 - (-14) = -21 + 14 = -7

Step-by-step explanation:

A - and a - make a +. So -21 - (-14) makes -21 + 14. Solve to get -7.

Hope it helps!

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I need help with this please

kodGreya [7K]

1/5(2x - 10) + 4x = -3(1/5x + 4)
0.4x - 2 + 4x = -0.6x - 12
4.4x - 2 = -0.6x - 12
5x - 2 = -12
5x = -10
x = -2

6 0

2 years ago

Read 2 more answers

Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and t

WINSTONCH [101]

Answer:

Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.

How long will it take for this population to grow to a hundred rodents? To a thousand rodents?

Step-by-step explanation:

Use the initial condition when dp/dt = 1, p = 10 to get k;

$\frac{dp}{dt} =kp^2\\\\1=k(10)^2\\\\k=\frac{1}{100}$

Seperate the differential equation and solve for the constant C.

$\frac{dp}{p^2}=kdt\\\\-\frac{1}{p}=kt+C\\\\\frac{1}{p}=-kt+C\\\\p=-\frac{1}{kt+C} \\\\2=-\frac{1}{0+C}\\\\-\frac{1}{2}=C\\\\p(t)=-\frac{1}{\frac{t}{100}-\frac{1}{2} }\\\\p(t)=-\frac{1}{\frac{2t-100}{200} }\\\\-\frac{200}{2t-100}$

You have 100 rodents when:

$100=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{100} \\\\2t=98\\\\t=49\ months$

You have 1000 rodents when:

$1000=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{1000} \\\\2t=99.8\\\\t=49.9\ months$

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2 years ago

C)PLEASE MAN PEOPLE ARE USING ME FOR POINTS

UNO [17]

The measures of spread include the range, quartiles and the interquartile range, variance and standard deviation. Let's consider each one by one.

Interquartile Range:

Given the Data -> First Quartile = 2, Third Quartile = 5

Interquartile Range = 5 - 2 = 3

Range: 8 - 1 = 7

Variance:

We start by determining the mean,

$\:1+\:2+\:3+\:3+\:3+\:5+\:8 / 7 = 3.57$

n = number of numbers in the set

Solving for the sum of squares is a long process, so I will skip over that portion and go right into solving for the variance.

$\sum _{i=1}^n\frac{\left(x_i-\bar{x}\right)^2}{n-1},\\\\=> SS/n - 1\\\\=> 31.714/7 - 1\\=> 5.28571$

5.3

Standard Deviation

We take the square root of the variance,

$\sqrt{5.28571} = 2.29906$

2.3

If you are not familiar with variance and standard deviation, just leave it.

3 0

2 years ago

Read 2 more answers

The cube of twice a number

raketka [301]

Answer:

The cube of twice a number.

Twice a quantity usually indicates to take two of the things in question; usually this indicates to multiply by 2. Thus "twice a number x" can be written symbolically as 2x. If this is part of a problem, say twice a number x is 6, then we can rewrite algebraically as 2x=6; dividing both sides by 2 yields x=3.

Step-by-step explanation:

have a nice day, please give me brainliest

3 0

2 years ago

Can someone help me plead

andrew-mc [135]

Answer:

a. 2^3

b. 3^4

c. 4^3 × 5^2

d. 9^4 × 7^2

Step-by-step explanation:

The following equations are given

a. 2 × 2× 2

b. 3 × 3 × 3 × 3

c. 4 × 4 × 4 × 5 × 5

d. 9 × 7 × 9 × 9 × 7 × 9

We need to find the index notation for the above equations

a. 2^3

b. 3^4

c. 4^3 × 5^2

d. 9^4 × 7^2

In this way it should be done

The same would be relevant

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2 years ago