Answer:
x = 8
z = 93°
You had to solve the equation 13x-17=14x-25 and than solve {360-(87*2)} /2
Answer:
8 grams
Step-by-step explanation:
The balance is in equilibrium, so the weights of the two sides are equal.
Let the weight of a square be s.
Left side: 2s + 4
Right side: s + 3(4) = s + 12
The weights are equal, so we set the two expressions equal.
2s + 4 = s + 12
s = 8
Answer: The weight of a square is 8 grams.
Question 2: The first step was the combine the like terms; in this example he is subtracting the 3x on both sides of the =.
Well if finding X you get 4,-7 when you simplify the whole equation you get that as well.
62 percent of 80 is more
Step-by-step explanation:
the 62 percent of 80 comes out to 49.6 people and the other one comes out to 42 people
i dont know how to explain how to do it
Answer: The graph in the bottom right-hand corner
(see figure 4 in the attached images below)
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Explanation:
Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.
Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.
After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.