3 years ago

Determine the type of correlation represented in the scatter plot below.

Mathematics

2 answers:

vesna_86 [32]3 years ago

8 0

The answer is F because it constantly decreases at about the same amount

Ira Lisetskai [31]3 years ago

4 0

Answer:

f is correct

Step-by-step explanation:

You might be interested in

Giveaway time!!! Get your free 50 points

Mumz [18]

Answer:

huh

Step-by-step explanation:

huh

4 0

2 years ago

Read 2 more answers

Which steps will help prevent the introduction of invasive species into an area?

madreJ [45]

Answer:

answer becit uses b

Step-by-step explanation:

but yass queen but annyway

4 0

3 years ago

Read 2 more answers

A piece of metal with a mass of 140 grams is placed into a graduated cylinder containing 50.0. When the metal was put in the cyl

34kurt

The density would be 7g/ml.

3 0

3 years ago

Read 2 more answers

Percentages Just finish the sentences

Soloha48 [4]

The answer for 80% of games is 16 games is 12.8.

7 0

3 years ago

Read 2 more answers

In the third week of July, a random sample of 40 farming regions gave a sample mean of x = $6.88 per 100 pounds of watermelon. A

suter [353]

Answer:

a. [6.6350,7.3950]

b. ME=0.5150

Step-by-step explanation:

a. Given that n=40, $\bar x=6.88$ and that: $z_{\alpha/2}=z_{0.05}=1.645$

The required 90% confidence interval can be calculated as:

$\bar x\pm(margin \ of \ error)\\\\\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\\\6.88\pm(1.645\times \frac{1.98}{\sqrt{40}})\\\\=[6.3650,7.3950]$

Hence, the 90% confidence interval for the population mean cash value of this crop is [6.6350,7.3950]

b. The margin of error at 90% confidence interval is calculated as:

$ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\\\=(1.645\times \frac{1.98}{\sqrt{40}})\\\\=0.5150$

Hence, the margin of error is 0.5150

8 0

4 years ago