Answer:
C = 5.
Step-by-step explanation:
First, you need to remember that:
For the function:
h(x) = Sinh(k*x)
We have:
h'(x) = k*Cosh(k*x)
and for the Cosh function:
g(x) = Cosh(k*x)
g'(x) = k*Cosh(k*x).
Now let's go to our problem:
We have f(x) = A*cosh(C*x) + B*Sinh(C*x)
We want to find the value of C such that:
f''(x) = 25*f(x)
So let's derive f(x):
f'(x) = A*C*Sinh(C*x) + B*C*Cosh(C*x)
and again:
f''(x) = A*C*C*Cosh(C*x) + B*C*C*Sinh(C*x)
f''(x) = C^2*(A*cosh(C*x) + B*Sinh(C*x)) = C^2*f(x)
And we wanted to get:
f''(x) = 25*f(x) = C^2*f(x)
then:
25 = C^2
√25 = C
And because we know that C > 0, we take the positive solution of the square root, then:
C = 5
Answer:
( 2×8) - [ ( 5 + 15 ) ÷ 5] = 32
Step-by-step explanation:
According to the scenario, computation of the given data are as follows,
Given equation = 2x18-5+15/5=32
First we multiply first two letters,
then ( 2 × 18) = 36
Now, we add 5 and 15 then divide it by 5,
So, ( 5 + 15 ) ÷ 5 = 20 ÷ 5 = 4
Now we subtract 4 from 36,
Then 36 - 4 = 32
Hence the correct parentheses = ( 2×8) - [ ( 5 + 15 ) ÷ 5] = 32
10 10 10 1 is 31 split into three tens and one one. I'm guessing this is what you meant.
Both formulas equal to y, so they are equivalent to one another.
3x-5 = -3x+4
+5. +5
3x = -3x+9
+3x. +3x
6x = 9
/6. /6
x = 1.5
3(1.5)-5 = y
4.5-5
y = -0.5
