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Eva8 [605]
3 years ago
8

12x=18-6y in slope intercept form

Mathematics
2 answers:
Verdich [7]3 years ago
6 0
Here for points sooo
Sidana [21]3 years ago
5 0

Answer: y = -2x +3

slope intercept form: y = mx +b

divide everything by 6.

2x = 3 - y

isolate y by subtracting 3 from both sides

2x - 3 = -y

divide by negative 1 to get positive y

-2x +3 = y

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leonid [27]

Answer:

The answer is 9.

Step-by-step explanation:

2 squared = 4

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3 years ago
Plz help I'll give brainy!!!
marta [7]

Answer:

see below

Step-by-step explanation:

we are given a exponential function

\displaystyle y =   \left(1/5\right) ^{x}

we want to figure out the missing values of y for x i.e (-2,-1, and 2) to do we can consider substituting so,

when x is -2 y should be

\displaystyle y =   \left(1/5\right) ^{ - 2}

rewrite ⅕ in exponent notation:

\displaystyle y =   \left((5) ^{ - 1} \right) ^{ - 2}

by law of exponent we obtain:

\displaystyle y =   (5) ^{ 2}

simplify square:

\displaystyle y =   \boxed{ 25}

when x is -1:

\displaystyle y =   \left(1/5\right) ^{ - 1}

rewrite ⅕ in exponent notation:

\displaystyle y =   \left((5) ^{ - 1} \right) ^{ - 1}

use law of exponent which yields:

\displaystyle y =    \boxed5

when x is 3:

\displaystyle y =   \left(1/5\right) ^{ 3}

by law of exponent we obtain:

\displaystyle y =   1/ {5}^{3}

simplify square which yields:

\displaystyle y =   \frac{1}{ \boxed{125}}

5 0
3 years ago
Point A lies on the circle and has an x-coordinate of 1.
stellarik [79]

Answer:

\sqrt{(0-y)^{2}+(0-1)^{2}}=2

Step-by-step explanation:

we know that

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The distance from the center of the circle (origin) to the point A must be same at the radius

so

Applying the formula's distance between two points

point A( 1,y) and point (0,0)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

2=\sqrt{(0-y)^{2}+(0-1)^{2}}

rewrite

\sqrt{(0-y)^{2}+(0-1)^{2}}=2

3 0
3 years ago
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The answer would be 12
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4 years ago
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A garrison of 60 men had provisions for 90 days. If 15 men left the garrison. how long would the provisions last?​
WARRIOR [948]
The answers is 36 days
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