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andrezito [222]
3 years ago
13

The counters in a bag are red or blue one fifth of the counters are red work out the ratio of red counters to blue counters

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
5 0
Nah of red and the ratio no se Natha
Natali5045456 [20]3 years ago
3 0

Answer:

The counters in a bag are red or blue. Assume 5 in total.

Step-by-step explanation:

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3 years ago
Please help me solve this it's due tmr
gladu [14]
This problem is about adding up the surface area of all of the surfaces he will paint and then dividing it by 200 to find how many gallons he will need to buy. Since he won't paint his roof, we need to find the surface area of every square foot that he will paint. So to do this it is just doing the area formula A=L*W for rectangles, and A=1/2*H*W, for the triangles. So he will paint 2 triangular spaces, the front and the back, plus he will paint 4 rectangular walls. So let's do the very front section first. When looking straight at the front u see a rectangle and a triangle. So let's find the area of both. The rectangle we need to plug in the length, or in other words the height, which is 8 feet. The width is 12 ft. So what is 8 times 12? It is 96 sq. ft. So 96 square feet is the front rectangle. There is another rectangle on the back of the shed that's the same dimensions that he will paint, so instead of doing that again we can just multiply 96 sq ft by 2, which is 192 sq ft. Now let's do the 2 triangles he will paint. Both of the triangles are the same exact dimensions, so what we do is plug the numbers in, the height is 4 ft. So it looks like 1/2 * 4 ft * 12 ft. 1/2 of 4 is 2, so multiply 2 by 12, which equals 24. So one of the triangles has 24 sq ft, but since there is another one on the back side that he will paint, we multiply that by 2 to save time. This will equal 48 sq ft. Now all we have to do is the other two walls on the sides. This is the same formula, A= L*W. so length is the same as the other 2 rectangles because they are the same height, so the length is 8 ft. And the width is 20 ft. What is 20 times 8? 20 times 8 is 160 sq ft. Since there is another wall just like that on the other side, we multiply that by 2 to get 320 sq ft. Now we add all of it up. 320+ 48+ 192= 560 sq ft. So he will paint 560 sq ft. What is 560 divided by 200? It will be 2.8, so he will have to buy 2.8 gallons of paint. Since you can't buy 2.8 gallons of paint, he will really buy 3 gallons, so he will have some left over. Since 1 gallon cost $48, we will need to multiply 48 by 3, to give us 144. So he will spend $144 on paint to paint his shed. I hope this helps
8 0
3 years ago
A certain group of test subjects had pulse rates with a mean of beats per minute and a standard deviation of beats per minute. U
Lisa [10]

Answer: is this it?

Step-by-step explanation:

5 0
1 year ago
Compute the surface area of the portion of the sphere with center the origin and radius 4 that lies inside the cylinder x^2+y^2=
Tom [10]

Answer:

16π

Step-by-step explanation:

Given that:

The sphere of the radius = x^2 + y^2 +z^2 = 4^2

z^2 = 16 -x^2 -y^2

z = \sqrt{16-x^2-y^2}

The partial derivatives of Z_x = \dfrac{-2x}{2 \sqrt{16-x^2 -y^2}}

Z_x = \dfrac{-x}{\sqrt{16-x^2 -y^2}}

Similarly;

Z_y = \dfrac{-y}{\sqrt{16-x^2 -y^2}}

∴

dS = \sqrt{1 + Z_x^2 +Z_y^2} \ \ . dA

=\sqrt{1 + \dfrac{x^2}{16-x^2-y^2} + \dfrac{y^2}{16-x^2-y^2} }\ \ .dA

=\sqrt{ \dfrac{16}{16-x^2-y^2}  }\ \ .dA

=\dfrac{4}{\sqrt{ 16-x^2-y^2}  }\ \ .dA

Now; the region R = x² + y² = 12

Let;

x = rcosθ = x; x varies from 0 to 2π

y = rsinθ = y; y varies from 0 to \sqrt{12}

dA = rdrdθ

∴

The surface area S = \int \limits _R \int \ dS

=  \int \limits _R\int  \ \dfrac{4}{\sqrt{ 16-x^2 -y^2} } \ dA

= \int \limits^{2 \pi}_{0} } \int^{\sqrt{12}}_{0} \dfrac{4}{\sqrt{16-r^2}} \  \ rdrd \theta

= 2 \pi \int^{\sqrt{12}}_{0} \ \dfrac{4r}{\sqrt{16-r^2}}\ dr

= 2 \pi \times 4 \Bigg [ \dfrac{\sqrt{16-r^2}}{\dfrac{1}{2}(-2)} \Bigg]^{\sqrt{12}}_{0}

= 8\pi ( - \sqrt{4} + \sqrt{16})

= 8π ( -2 + 4)

= 8π(2)

= 16π

4 0
2 years ago
Y = 8/x<br> Input<br> Output
ExtremeBDS [4]
1.) -2
2.) -4
3.) 4
4.)2
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3 years ago
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