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3 years ago

13

Raul bought a soft drink and a sandwich for $9.90 . Which is he price of each if the sandwich cost 3.5 times as much as the soft

drink

1 answer:

Radda [10]3 years ago

8 0

B. Sandwich costs $7.70 and the soda costs $2.20

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To the nearest tenth, what is the area of the shaded segment when JA = 8 ft?

dlinn [17]

I think you forgot to give the diagram along with the question. Considering 8 ft as the radius, we can find the area by the formula described below.
Area = pi * (Radius) ^2
= 3.14 * (8)^2
= 3.14 * 64
= 200.96
So the area of the shaded portion would be 200.96 square feet. I hope that this answer has come to your help.

3 0

3 years ago

What is the difference between 450.2 and 6.957

Bas_tet [7]

Answer: 443.243 and round your answer

Step-by-step explanation:

if you’re looking for difference just subtract the two numbers

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3 years ago

The expression 6x2 gives the surface area of a cube, and the expression x3 gives the volume of a cube, where x is the length of

AVprozaik [17]

Answer:

surface area of the cube is 96m² and the volume is 64m³

Step-by-step explanation:

Surface area of the cube = 6x²

x is the side length

Given

x = 4metres

Surface area of the cube = 6(4)²

Surface area of the cube = 6(16)

Surface area of the cube = 96m²

Volume of the cube = x³

Volume of the cube = 4³

Volume of the cube = 64m³

Hence the surface area of the cube is 96m² and the volume is 64m³

3 0

3 years ago

Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)

UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600$

Therefore, the probability is

$P=\frac{12117600}{53524680}\\\\P=0.226$

b) We calculate the probability that are at least 2 red balls.

We calculate the probability withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations: for 1 red balls

$C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848$

Therefore, the probability is

$P_1=\frac{16138848}{53524680}\\\\P_1=0.3$

We calculate the number of favorable combinations: for none red balls

$C_7^{34}=5379616$

Therefore, the probability is

$P_0=\frac{5379616}{53524680}\\\\P_0=0.1$

Therefore, the the probability that are at least 2 red balls is

$P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6$

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056$

Therefore, the probability is

$P=\frac{44056}{53524680}\\\\P=0.0008$

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

$P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\$

Let Y, event that exactly 3 blue balls selected.

$P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\$

We have

$P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12$

Therefore, we get

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74$

8 0

3 years ago

A recipe that serves 24 people calls for 4 liters of lemon-lime soda, 2 pints of sherbet, and 6 cups of ice. How much of each in

bogdanovich [222]

Split each ingredient in half 2 liters of lemon lime soda 1 pint of sherbet and 3 cups of ice

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3 years ago