A biased example: Asking students who are in line to buy lunch
An unbiased example: Asking students who are leaving/going to lunch(<em>NOT buying </em><em>lunch</em><em />).
But in this case, the answer choices can be... confusing.
Don't panic! You're given numbers and, of course, your use of logic.
Answer choice A: 100 students grades 6-8
Answer choice B: 20-30 students any <em>one</em> grade<em></em><em>
</em>Answer choice C: 5 students
<em></em>Answer choice D: 50 students grade 8
An unbiased example would be to choose students from <em>any grade.</em> So we can eliminate choices B and D.
Now, the question wants to <em>estimate how many people at your middle school buy lunch.</em> This includes the whole entire school, and if you are going to be asking people, you aren't just going to assume that if 5 people out of 5 people you asked bought lunch, the whole school buys lunch.
So, to eliminate all bias and/or error by prediction, answer choice A, the most number of students, is your answer.
Answer:
The value of P (A ∩ B) is 0.25.
Step-by-step explanation:
Independent events are those events that do not effect the occurrence of each other, i.e. if event <em>X </em>and <em>Y</em> are independent then the occurrence of <em>X</em> and <em>Y </em>are not influenced by each other.
For independent events <em>X</em> and <em>Y</em> the joint probability of <em>X</em> and <em>Y</em> is:

It is provided that events <em>A</em> and <em>B </em>are independent of each other.
And P (A) = P (B) = 0.50.
Compute the value of P (A ∩ B) as follows:

Thus, the value of P (A ∩ B) is 0.25.
Answer: 24.8
Explanation: If Henry is halving a number, that means he's dividing it by 2, getting two halves. You would get the original number by undoing that division, or multiplying the product by 2.
2 x 12.4 = 24.8
The answer is 20/27. 8/9x5/6=20/27.
Answer: It's a tie between f(x) and h(x). Both have the same max of y = 3
The highest point shown on the graph of f(x) is at (x,y) = (pi,3). The y value here is y = 3.
For h(x), the max occurs when cosine is at its largest: when cos(x) = 1.
So,
h(x) = 2*cos(x)+1
turns into
h(x) = 2*1+1
h(x) = 2+1
h(x) = 3
showing that h(x) maxes out at y = 3 as well
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Note: g(x) has all of its y values smaller than 0, so there's no way it can have a max y value larger than y = 3. See the attached image to see what this graph would look like if you plotted the 7 points. A parabola seems to form. Note how point D = (-3, -2) is the highest point for g(x). So the max for g(x) is y = -2