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Novay_Z [31]
3 years ago
11

Necesitooo su ayudaaa​

Mathematics
1 answer:
dem82 [27]3 years ago
8 0

Answer:

in1 ans is 5

in2ans is 9 ok

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Eden has a part time job. She gets paid £7. 20 per hourthis week she worked for 18 1/2 hourswork out Eden's total pay for this w
Dafna1 [17]

Answer:

$133.20

Step-by-step explanation:

Since the amount of hours she worked isn't a whole number, we can first separate 18 and 1/2 and work the problem out one at a time.

1. Multiply 7.20 by 18 to get 129.60

2. Multiply 0.50 by 7.20 to get 3.60.

3. Add 129.60 and 3.60 together to get the answer, 133.20.

5 0
2 years ago
find the roots of the quadratic equation x^2-6x+k=0.giventhat one root is three times the other and that k is a constant.Also fi
arlik [135]

x_{1}  = 3x_{2}  \\ x_{1}  - 3x_{2}  = 0 ←relation \: 1\\ x_{1}  + x_{2}  = 6 ←relation \: 2

(x_{1},x_{2}) : (4.5,1.5)

k = x_{1}x_{2} = 4.5 \times 1.5 = 6.75

7 0
1 year ago
If the second term of a geometric sequence of real numbers is -2 and the fifth term is 16 then what is the fourteenth term?
Agata [3.3K]
<h3>Given</h3>

A geometric sequence such that ...

a_2=-2\quad\text{and}\quad a_5=16

<h3>Find</h3>

a_{14}

<h3>Solution</h3>

We can use the ratio of the given terms to find the common ratio of the sequence, then use that to find the desired term from one of the given terms. We don't actually need the common ratio (-2). All we need is its cube (-8).

a_2=a_1r^{(2-1)}=a_1r^1\\a_5=a_1r^{(5-1)}=a_1r^4\\a_{14}=a_1r^{(14-1)}=a_1r^13=a_5r^9\\\\\dfrac{a_5}{a_2}=\dfrac{a_1r^4}{a_1r^1}=r^3=\dfrac{16}{-2}=-8\\\\r^9=\left(r^3\right)^3=(-8)^3=-512\\a_{14}=a_5(-512)\\\\a_{14}=-8192

7 0
3 years ago
What is the sum of 20x^2-10x-30
ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

ax^{2} +bx+c=0

The sum of the roots is equal to

-\frac{b} {a}

in this problem we have

20x^{2} -10x-30=0  

so

a=20\\b=-10\\c=-30

substitute

-\frac{(-10)} {20}=0.5

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

a=20\\b=-10\\c=-30

substitute

x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}

x=\frac{10\pm\sqrt{2,500}} {40}

x=\frac{10\pm50} {40}

x=\frac{10+50} {40}=1.5

x=\frac{10-50} {40}=-1

The roots are x=-1 and x=1.5

The sum of the roots are

-1+1.5=0.5 ----> is ok

5 0
3 years ago
A packet of sweets costs $2.25.
harkovskaia [24]
Felipe pays 1.4 dollars
5 0
3 years ago
Read 2 more answers
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