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Gwar [14]
3 years ago
8

The running back for the Bulldogs football team carried the ball 9 times for a total loss of 20

Mathematics
1 answer:
Ivahew [28]3 years ago
3 0
Yeah the answer is 16. 


And could I get brainiest because I need to get it one more time to get to my next rank
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Three times the difference of a number and seven is negative three. Fi<br> nd the number.
postnew [5]
3(x-7)=-3
3x-21=-3
3x=18
x=6
6 0
3 years ago
Solve the system of equations
IceJOKER [234]
<h3>Answer:</h3>

c) there are infinitely many solutions

<h3>Explanation:</h3>

Add x to the <em>first equation</em> to put it in standard form:

... x + y = 3

Divide the <em>second equation</em> by the common factor of all terms, 2, to put it in standard form:

... x + y = 3

These two equations describe the same line. Every point on the line is a solution to both equations, so there are infinitely many solutions. (We say these equations are "dependent.")

3 0
3 years ago
Hi I’m new can someone help me on this (PLZ NO LINKS)
Ymorist [56]
Complementary angles add up to 90 degrees.
So to find A you would need to add A and B together and equal it to 90 (3x+25+5x-7=90)
Combine like terms together (8x+18=90)
Subtract 18 from night sides (8x=72)
Divide by 8 on both sides (x=9)
Then to find A substitute x into its equation (3(9)+25)=(27+25)=52

A=52 I think
7 0
2 years ago
P/3 - 2 provide an algebraic expression for p divided by 3 plus 2
Sauron [17]
\frac{p}{3}+2
4 0
3 years ago
How do i find the area of a trapezoid (pictures provided)
scoray [572]

Answer:

(10x - 5) square units.

Step-by-step explanation:

Let the lengths of equal sides be x units.

Hence, AB + AD + DC = x + x + x = 3x

Therefore, BC = 3x - 2

Area  \: of \:  trapezoid  \\ =  \frac{1}{2} (AD + BC)  \times 5 \\  = \frac{1}{2} (x + 3x - 2)  \times 5  \\ = \frac{1}{2} (4x - 2)  \times 5  \\ = \frac{1}{2} \times 2 (2x - 1)  \times 5  \\  = (2x - 1) \times 5 \\  = (10x - 5) \:  {units}^{2}

5 0
3 years ago
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