Question

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Answer 1

Given:

$10x>8(3x-2)-12$

To find:

The values of x.

Solution:

We have,

$10x>8(3x-2)-12$

$10x>8(3x)+8(-2)-12$      (Distributive property)

$10x>24x-16-12$

$10x>24x-28$             (Combining like terms)

Add 28 on both sides.

$10x+28>24x$

Subtract 10x from both sides.

$28>24x-10x$

$28>14x$

Divide both sides by 14.

$\dfrac{28}{14}>x$

$2>x$

Therefore, the values of x are all real numbers less than 2, i.e., x<2 .