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3 years ago

Find the equation of the line.

Mathematics

1 answer:

Alex3 years ago

6 0

Answer:

Y=4x-9

Step-by-step explanation:

The line is at -9 when it's on the y axis

It goes up 4 over 1

You might be interested in

The following information is obtained from two independent samples selected from two normally distributed populations.

AysviL [449]

A. The point estimate of μ1 − μ2 is calculated using the value of x1 - x2, therefore:

μ1 − μ2 = x1 – x2 = 7.82 – 5.99

μ1 − μ2 = 1.83

B. The formula for confidence interval is given as:

Confidence interval = (x1 –x2) ± z σ

where z is a value taken from the standard distribution tables at 99% confidence interval, z = 2.58

and σ is calculated using the formula:

σ = sqrt [(σ1^2 / n1) + (σ2^2 / n2)]

σ = sqrt [(2.35^2 / 18) + (3.17^2 / 15)]

σ = 0.988297

Going back to the confidence interval:

Confidence interval = 1.83 ± (2.58) (0.988297)

Confidence interval = 1.83 ± 2.55

Confidence interval = -0.72, 4.38

3 0

3 years ago

Answer this question for me ASAP PLEASE. Please show all work.

ziro4ka [17]

9514 1404 393

Answer:

acute scalene triangle

Step-by-step explanation:

The largest angle is acute, and all sides are different lengths. The triangle is an<em> acute scalene triangle</em>.

____

The magnitudes of the coordinate differences are ...

WX = (7, 5), XY = (2, 7), WY = (9, 2)

The two sides that are closest in length are ...

WX = √(49+25) = √74

WY = √(81 +4) = √85

Obviously, these are different lengths.

You can get a clue by comparing the numbers whose squares you are adding:

7^2 +5^2 > 7^2 +2^2 . . . . . WX > XY

9^2 +2^2 > 7^2 +2^2 . . . . WY > XY

so, the only question is relation between WX and WY. We note that the length of WX is less than one of the coordinate differences of WY, so we know WY is the longest. (√74 < 9)

We can tell from the graph that angle X (opposite longest side WY) is an acute angle, so the triangle is acute.

7 0

2 years ago

Find a power series for the function, centered at c. g(x) = 4x x2 2x − 3 , c = 0

BartSMP [9]

The power series for given function $g(x)=\frac{4x}{(x-1)(x+3)}$ is $g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$

For given question,

We have been given a function g(x) = 4x / (x² + 2x - 3)

We need to find a power series for the function, centered at c, for c = 0.

First we factorize the denominator of function g(x), we have:

$\Rightarrow g(x)=\frac{4x}{(x-1)(x+3)}$

We can write g(x) as,

$\Rightarrow g(x)=\frac{1}{x-1}+\frac{3}{x+3}\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1+\frac{x}{3} }\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1-(-\frac{x}{3} )}\\$