Period:
1 answer:
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Answer:
See explanation
Step-by-step explanation:
The question is incomplete as the required trapezoid is not given. SO, I will answer using genera rules.
The area of a trapezoid is:
Where
parallel sides
Assume that:
The formula becomes
Answer:
Dy/dt = 11.67 ft/s
Step-by-step explanation: See Annex
In Annex, Triangles ACE and BCD are similar then, we can write
( y- x ) / y = 6 / 15
15*y -15*x = 6*y
15*y - 6*y = 15*x
9*y = 15*x
y = (15/9)*x
Differentiating with respect time on both sides of the equation we get
Dy/dt = (15/9) Dx/dt (1)
Where we know Dx/dt = 7 ft/s, and according to (1) Dy/dt does not depend on x (distance between man and the pole, only depend on the speed f the man
Dy/dt = (15/9) * 7
Dy/dt = 11.67 ft/s
hmmm first off let's convert the √3 +i to trigonometric form, and then use De Moivre's root theorem, bearing in mind that √3 and i or 1i are both positive, meaning we're on the I Quadrant.