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lisabon 2012 [21]
3 years ago
10

Which of the following systems has an infinite number of solutions?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

Answer:

C. x+y = 1 and -x-y = -1

Step-by-step explanation:

Remember that if a system of equations has an infinite number of solutions, then the resulting equation from using the first step of the elimination method would have no variables and would be true.  

1) Let's try canceling out the equations in option C, x+y =-1 and -x-y =-1. Add the two equations together. (Work shown in attached picture.)

2) All of the terms cancel out with each other, leaving only a true statement of 0 = 0. Thus, option C is the answer.  

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Simplify the expression:<br> -1 + -1 + -3h + -8h
ValentinkaMS [17]

Answer:

-2 + 11h

Step-by-step explanation:

To simplify this equation, you can first combine like terms:

( -1 + -1 ) + ( -3h + -8h )

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3 0
3 years ago
Approximately how many times greater is 6 x 10^-5 than 5 x 10^-9
8_murik_8 [283]

Answer: 6 \times 10^{-5} is 1.2 \times 10^4. times greater than 5 \times 10^{-9}.


Step-by-step explanation:

We are given two numbers.

First number  : 6 \times 10^{-5}.

Second number : 5 \times 10^{-9}.

In order to find how many times   6 \times 10^{-5} is greater than 5 \times 10^{-9}, we need to divide first number by second number.

Therefore,

6 \times 10^{-5} ÷ 5 \times 10^{-9}

or \frac{6 \times 10^{-5}}{5 \times 10^{-9}}

First we would divide 6 by 5.

On dividing 6 by 5, we get 1.2.

Now, we would divide 10^-5 by 10^-9.

In order to divide them, we can apply quotient rule of exponents \frac{a^m}{a^n} =a^{m-n}.

We get

\frac{10^{-5}}{10^{-9}}  = 10^{-5-(-9)} = 10^{-5+9} = 10^4.

Therefore,

\frac{6 \times 10^{-5}}{5 \times 10^{-9}} = 1.2 \times 10^4.

So, we could say finally 6 \times 10^{-5} is 1.2 \times 10^4. times greater than 5 \times 10^{-9}.

8 0
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kogti [31]
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7 0
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