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leva [86]
3 years ago
13

Another brain test ;-; Answer the question (s) below!

Mathematics
2 answers:
babymother [125]3 years ago
7 0

Answer:1/4

Step-by-step explanation:

PilotLPTM [1.2K]3 years ago
4 0

3. Harold spent 1/4 of a fraction of an hour milking each group.

4. Rosanne and her family played 16 different games on their vacation trip.

5. Girish has 12 batches of bread.

6. Jason can cut 12 pieces of sausage.

7. Hubert cut 9 pieces of yarn.

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Find x - y subtracted from 0.
Otrada [13]

Answer: wouldn’t that just be 0?

Step-by-step explanation:

7 0
3 years ago
18x^2-8=0 I have to factor it but I’m not sure how to! Please help!
PilotLPTM [1.2K]

Answer:

hope it helps...........

5 0
3 years ago
Read 2 more answers
5621602830-32. NDHS BUBUBHUWEBHUBHUBHBSBSHDBFHBDHBDFBFBD
SOVA2 [1]

Answer:

me 2

Step-by-step explanation:

3 0
4 years ago
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Fifty-five percent of the members of the junior varsity swim team wear glasses. Of the team memebers who do not wear glasses, 30
GarryVolchara [31]

the probability that a randomly chosen member of the JV swim team does not wear glasses and is in the 10th grade is 14%.

Given, the members of the junior varsity swim team wear glasses is 55%.

And the members of junior varsity swim team who do not wear glasses and in 10th grade is 30%.

Let the total no. of members be x.

So, the members of the junior varsity swim team wear glasses (55%),will be

0.55x.

The total number of members not wearing glasses, will be

x - 0.55 x = 0.45 x.

Now, the no. of members not wearing glasses and in 10th grade will be,

\frac{0.45x\times30}{100} =0.135x

We know that the probability of an event E, P(E) will be,

P(E)=\frac{No.\ of Favourable\ outcomes}{total \ no. \ of \ outcomes}

So, the probability for no. of members not wearing glasses and in 10th grade will be,

P(E)=\dfrac{0.135x}{x}

P(E)=0.135\\\\P(E)=13.5 \%

Hence the nearest whole percent of probability is 14%.

For more details on probability follow the link:

brainly.com/question/795909

8 0
3 years ago
Janna spends 1.25 hours of the 8-hour word day answering e-mail messages. What percentage of the work day is this time?
timurjin [86]
Around 16% rounded...........
6 0
3 years ago
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