X-4y=6. 5x+y=8
minus X from both sides
4y=6. 4x+y=8
minus y from both sides
3y=6. 4x=8
y=2
X=-2
Answer:
D. a = m + 30
Step-by-step explanation:
It's not A, because that would be dividing Malik's score in half to get Alexia's score.
B only works for the first line.
C is adding 10 to Malik's score, and the difference is greater than that...it's 30 points.
Answer:
After 2 hours: -6°C.
After 5 hours: -15°C.
After 
hours: -1.5°C
1 hour ago: 3°C.
3 hours ago: 9°C.
4.5 hours ago: 13.5°C.
To find these values, you simply need to multiply the hours elapsed by 3°C. Subtract from 0°C for future temperatures, and ADD to 0°C for the past.
Let's say you are solving for the temperature in 5 hours. All you need to do is:
3°C× 5= 15°C. 0°C-15°C= -15°C
For the temperature 3 hours AGO, what you will need to do instead is:
3°C×3= 9°C. 0°C+ 9°C= 9°C.
9514 1404 393
Answer:
- y -3 = 5(x -1)
- y +1 = -3(x +2)
- y +7 = -1/4(x -4)
Step-by-step explanation:
When you are given a point and a slope, and asked for the equation in point-slope form, it is simply a matter of putting the given numbers into the appropriate places in the equation template.
y -k = m(x -h) . . . . . . point (h, k), slope m
__
1. y -3 = 5(x -1) . . . . . . point (1, 3), slope 5
2. y +1 = -3(x +2) . . . . point (-2, -1), slope -3
note that for k=-1, -k = -(-1) = +1; similarly the value of -h becomes +2
3. y +7 = -1/4(x -4) . . . point (4, -7), slope -1/4
Answer:
x=29
∠C=93°
Step-by-step explanation:
180°-52°-35°=3(x+2)°
180°-87°=(3x)°+6°
93°=(3x)°+6°
(3x)°=87°
x=
x=29
∠C=3(x+2)°
=3(29+2)°
=3(31)°
=93°
