You need to have the radius of the circle , or it’s area
The first thing to do is to work out the biggest number that goes into bother 24 and 3. As the only that goes into three- other than 1- is itself, one can assume this is the number we are looking for.
Next, divide bother numbers by 3.
24 / 3 = 8
3 / 3 = 1
You now take 3 out of the brackets, and leave 8 and 1. 24x / 3 = 8x.
3(8x + 1)
Answer:
Step-by-step explanation:
Basically those lines next to the problem are absolute value signs. Get rid of those then your problem is solved.
Answer:
![\displaystyle \frac{d}{dx}[3x + 5x] = 8](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5B3x%20%2B%205x%5D%20%3D%208)
General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Multiplied Constant]: ![\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<u>Step 2: Differentiate</u>
- Simplify:
- Derivative Property [Multiplied Constant]:
![\displaystyle y' = 8\frac{d}{dx}[x]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%208%5Cfrac%7Bd%7D%7Bdx%7D%5Bx%5D)
- Basic Power Rule:
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
Considering the given stem-and-leaf plot, the quartiles are given as follows:
- The first quartile is of 67.5.
- The second quartile, which is the median, is of 84.5.
- The third quartile is of 91.5.
<h3>What are the median and the quartiles of a data-set?</h3>
- The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
- The first quartile is the median of the first half of the data-set.
- The third quartile is the median of the second half of the data-set.
There is an even number of elements(26), hence the median is the mean of the 13th and 14th elements, which are 83 and 86, hence:
Me = (83 + 86)/2 = 84.5.
The first half has 12 elements, hence the first quartile is the mean of the 6th and 7th elements, which are 67 and 68, hence:
Q1 = (67 + 68)/2 = 67.5.
The third half also has 12 elements, starting at the second 86, hence the third quartile is the mean of the 6th and 7th elements of this half, hence:
Q3 = (91 + 92)/2 = 91.5.
More can be learned about the quartiles of a data-set at brainly.com/question/28017610
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