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Mekhanik [1.2K]
3 years ago
6

URGENT!! PLEASE ANSWER!! Find all solutions to the equation. sin^2x + sin x = 0

Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0

Answer: Explanation:

We have:

sin

2

(

x

)

+

sin

(

x

)

=

0

;

[

0

,

2

π

)

⇒

sin

(

x

)

(

sin

(

x

)

+

1

)

=

0

⇒

sin

(

x

)

=

0

⇒

x

=

0

,

(

π

−

0

)

,

(

π

+

0

)

,

(

2

π

−

0

)

or

⇒

sin

(

x

)

+

1

=

0

⇒

sin

(

x

)

=

−

1

⇒

x

=

π

+

π

2

⇒

x

=

0

,

3

π

2

,

π

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

2) x = -2 , y = 2

3) no solution exists

Step-by-step explanation:

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{-2 x - 3 y = -2

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Hint: | Perform a substitution.

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{-2 x - 3 (2 x + 6) = -2

y = 2 x + 6

Hint: | Expand the left hand side of the equation -2 x - 3 (2 x + 6) = -2.

-2 x - 3 (2 x + 6) = (-6 x - 18) - 2 x = -8 x - 18:

{-8 x - 18 = -2

y = 2 x + 6

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for x:

{-8 x - 18 = -2

y = 2 x + 6

Hint: | Isolate terms with x to the left hand side.

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y = 2 x + 6

Hint: | Solve for x.

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Hint: | Perform a back substitution.

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Step-by-step explanation:

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