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balandron [24]
3 years ago
11

A proof in which you assume the opposite of what you want to prove is called what?

Mathematics
1 answer:
Taya2010 [7]3 years ago
4 0
Proof<span> by contradiction........... </span>
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what is the highest number in the world and what is the lowest number in the world explain your answer
artcher [175]
Positive infinity and negative infinity 

5 0
3 years ago
PLEASE HELP QUICK!!!!!! WILL GIVE BRAINIEST!!!!!! Don’t answer if you don’t know it please.
mojhsa [17]
I’m almost 100% sure it is: D. Graph D

Happy holidays and hope this helps!!
3 0
3 years ago
WILL GIVE BRAINLIEST! Find k so that (5, k) is equidistant from (–1, 2) and (3, 0).
pochemuha

Answer:

9

Step-by-step explanation:

So first I created 2 distance forumlas and set them equal to each other

\sqrt{(5+1)^2+(k-2)^2} =\sqrt{(5-3)^2+(k)^2}

then I simplified them

(5+1)^2+(k-2)^2 =(5-3)^2+(k)^2\\

36 + k^2 - 4k +4 = k^2 + 4

-4k + 36 = 0\\

4k = 36

k = 9

when k = 9, the two distances are equal

7 0
3 years ago
A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus
aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis H_0:\mu= 1.6 (the null hypothesis always have the equal sign).

We have to test the null hypothesis

H_0:\mu= 1.6

The significance level for this test is 0.05

Calculation of the t-statistic:

t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0
3 years ago
Solve the right triangle.
Tom [10]
Solve using trigonometry
tan(39)=24/b
b=24/tan(39)
so b=29.6
for c…
sin(39)=24/c
c=24/sin(39)
c=38.1
4 0
2 years ago
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