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3 years ago

Which relations represent a function?

Mathematics

1 answer:

MariettaO [177]3 years ago

7 0

Answer:

A, C, and F are functions.

Step-by-step explanation:

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Which is an equation of a circle with center (2, -1) that passes through the point (3, 4)?

iren2701 [21]

Equation of circle is (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
r^2 = (2 - 3)^2 + (-1 - 4)^2 = (-1)^2 + (-5)^2 = 1 + 25 = 26
Equation is (x - 2)^2 + (y + 1)^2 = 26

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3 years ago

If you want to buy an item in a store that costs $25 an is on sale for 10% off

kumpel [21]

Answer:

2.50$ off or 22.50$

Step-by-step explanation:

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3 years ago

Find m ABC (2x+14) (x+7)

Orlov [11]

Answer:

Last option 30°

damm sure about it

Step-by-step explanation:

value of x is 23 but value of Angle ABC will be x +7 i.e. 30

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2 years ago

Read 2 more answers

Sarah has 128 stickers. alex has 10 fewer stickers than sarah. how many stickers does Alex have.

nikitadnepr [17]

To get your answer you first subtract 10 from 128 which is 118.

4 0

3 years ago

Need help with homework

motikmotik

We have two points describing the diameter of a circumference, these are:

$\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}$

Recall that the equation for the standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

$M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})$

Now, we replace and solve:

$\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}$

The center of the circle is (-8,-7), so:

$\begin{gathered} h=-8 \\ k=-7 \end{gathered}$

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation:

$r^2=\Delta x^2+\Delta y^2$

In this case, we will solve the delta with the center coordinate and the B coordinate.

$\begin{gathered} r^2=((-4)-(-8))^2+((-10)-(-7)) \\ r^2=(-4+8)^2+(-10+7)^2 \\ r^2=4^2+(-3)^2 \\ r^2=16+9 \\ r^2=25 \\ r=5 \end{gathered}$

Therefore, the equation for the standard form of a circle is:

$\begin{gathered} (x-(-8))^2+(y-(-7))^2=25 \\ (x+8)^2+(y+7)^2=25 \end{gathered}$

In conclusion, the equation is the following:

$(x+8)^2+(y+7)^2=25$

4 0

10 months ago