Answer:

Step-by-step explanation:
we have

we know that

substitute

Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
Answer:
ebeuhebjdifjrjr
Step-by-step explanation:
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Answer:
C
Step-by-step explanation:
< open circle, not ≤
Answer:
period.
Step-by-step explanation: