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andre [41]
3 years ago
12

0.1784 to 2 decimal places

Mathematics
1 answer:
tia_tia [17]3 years ago
5 0
The answer I got was 0.18
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A total of 200 songs were played at a party in the ratio of 3 : 2 : 5. if the amount representing Vybez Kartel is 5 How many of
Jobisdone [24]

Answer:

100

Step-by-step explanation:

Because it would be the most common it would make no sense if any of the other options would represent the value of 2 and 3 if it had it would go over the amount of 200. But if they were represented by numbers 3 would be 60 and 2 would be 40 multiplying by two and ofc 5 would be 100.

6 0
2 years ago
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What is the equation of the graph below?
wlad13 [49]

<u>Answer:</u>

<u>y=cos(x+\pi )</u>

<u>Step-by-step explanation:</u>

From the graph, we can see that y = -1 when x  = 0.

So to check whether which of the given options is the equation of the given graph, we will set our calculator to the radian mode and then plug the value of x as 0.

1. y = cos(x + pi/2) = cos(0 + pi/2) = 0

2. y = cos(x+2pi) = cos(0+2pi) = 1

3. y = cos(x+pi/3) = cos(0+pi/3) = 1/2 = 0.5

4. y = cos(x+pi) = cos(0+pi) = -1


Therefore, the equation of this graph is y = cos(x+pi) = cos(0+pi) = -1.



5 0
3 years ago
A bag of concrete equals 1000 cu. Inches. Your customer already has 2 bags at home. How many more bags does he need to fill an a
adelina 88 [10]
From the information given;
1 bag of concrete = 1000 in^3
2 bags at home = 1000*2 = 2000 in^3

The available space has a volume of;

Volume = (5*12)*10*10 (Note: 1 ft = 12 inches)
Volume = 60*10*10 = 6000 in^3

The remaining volume = Available space - occupied space = 6000 - 2000 = 4000 in^2

1 bag = 1000 in^3
x bags = 4000 in^2

Then,
x = 1*4000/1000 = 4 bags.
This means 4 more bags of concrete will be required to fully fill the  space.
5 0
3 years ago
A seamstress needs to cut 15- inches pices of ribbons from a roll of ribbon that is 9 feet in length. What is the greatest numbe
sertanlavr [38]
The seamstress can cut 36, 15-inch pieces of ribbon from 5 rolls of 9 foot long ribbon.
8 0
3 years ago
Aidan is participating in an 8 mile walk for his favorite charity. The organizers used a coordinate grid to plot the course. The
Travka [436]

Answer:

Aidan is 2 miles far from the ending point when he reaches the water station.

Step-by-step explanation:

The locations of the starting point, water station and ending point are (3, 1), (3, 7) and (3, 9), all expressed in miles. First we determine the distances between starting and ending points and between starting point and water station by the Pythagorean Theorem:

From starting point to ending point:

D = \sqrt{(3-3)^{2}+(9-1)^{2}} (Eq. 1)

D = 8\,mi

From starting point to water station:

d = \sqrt{(3-3)^{2}+(7-1)^{2}} (Eq. 2)

d = 6\,mi

The distance between the water station and the ending point is:

s = D-d (Eq. 3)

s = 8\,mi-6\,mi

s = 2\,mi

Hence, Aidan is 2 miles far from the ending point when he reaches the water station.

3 0
3 years ago
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