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AleksandrR [38]
2 years ago
6

A polynomial is given below. 3x^6+2x^4-x^3+7

Mathematics
1 answer:
Harrizon [31]2 years ago
5 0

Answer: = 3x^6+2x^4−x^3+7 bc there are no like terms

Step-by-step explanation:

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Monica estimates the recipe makes about 5 cups of fruit salad. Which explanation describes whether Monica's estimate is reasonab
Darya [45]

Answer:

A.

Step-by-step explanation:

Not reasonable, Why did you put that as your answer?

The whole numbers add up to more then 4 cups.

5 0
3 years ago
A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the
Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

             P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample average age = 25 years

            \sigma = population standard deviation = 1.8 years

            n = sample of students = 36

            \mu = population average age

So, 98% confidence interval for the average age, \mu is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

                                                  = [ 25 - 2.3263 \times {\frac{1.8}{\sqrt{36} } , 25 + 2.3263 \times {\frac{1.8}{\sqrt{36} } ]

                                                  = [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0
2 years ago
In Mr. Harold's class there are 12 students. They each have 5 pencils. Some of the students, s, each lost 2 pencils. Now, the st
Katena32 [7]
The answer would be C. (12 x 5) - (s x 2) = 38.

This is because if there are 12 students with 5 pencils per student, we can say 12 x 5. Then, think of the phrase, two pencils lost per student. That would be 2s, or (s x 2). Since it’s lost, we would subtract that amount from 12 x 5.
3 0
3 years ago
PLEASE ANSWER ASAP! *PICTURE ATTACHED*
a_sh-v [17]

Answer:

Pls send the options so I can confirm the answer.

5 0
3 years ago
Suppose you have 18 more quarters than dimes. You have a total of $8.00. How many of each coin do you have? Use the substitution
kramer

Answer:

18 quarters = $4.50

8.00-4.50=3.50

10 dimes+10 quarters=$3.50

Answer= you have 10 dimes and 28 quarters

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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