we are given

To find x-intercept means we have to find zeros
and for finding zeros , we will use quadratic formula
and we have it has two x-intercepts
so, it's discriminant must be greater than 0
so, we will find discriminant

now, we can compare with


and then we can find a , b and c

now, we can find D


It has two x-intercepts
so,

now, we can solve for m


............Answer
It should be 986m
4(17x6)= 408
2(17x17)= 578
408+578=986
Plugging it in, we get (3)(2)+2y=-12 and 6+2y=-12. Subtracting 6 from both sides, we get -18=2y and dividing by 2 we get y=-9 to get (2, -9) since x is first in the pair
You can think of this question like the photo attached above.
Hi!
I think for b, the answer would be:
You can construct an angle that is one fourth the measure of angle JKL, by dividing angle either angle MKL or JKM in half.
This is because one-fourth is also equal to one quarter (1/4). If you split angle JKL into 4 equal angles, you would have an angle that is one-fourth the measure (original angle) of angle JKL.
I think for c, the answer would be:
You can construct a 15 degree angle from a given 60 degree angle, by dividing the 60 degree angle into 4 equal angles.
This would work, because each of the 4 angles would be 15 degrees.
Hope this helps! Best of luck!