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2 years ago

Solve for x. Someone please help me I really need it.

Mathematics

1 answer:

valkas [14]2 years ago

5 0

Answer: X= 3.75

HOPE THIS HELPS:)))))

Step-by-step explanation:

You might be interested in

Which statement makes the open sentence 12+3x=30

Sergio [31]

12 + 3x = 30 // what is x?
3x = 18
x = 6

6 0

3 years ago

There are 45 students in Lisa's class. 35 of the students are boys and rest are girls

geniusboy [140]

If the question is how many students are girls, than it's ten(10).

8 0

3 years ago

The circle below has a radius of 3 units . Find the area of the circle. Use 3.14 for π.

const2013 [10]

Answer:

28.26 units

Step-by-step explanation:

We know the radius of the circle is 3 units, so we'll end up plugging that into the formula.

A = π(3^2) or A = π * 3 * 3

When you substitute pi for 3.14, you'll end up getting 28.26 units.

Hope this helped! :)

6 0

2 years ago

$1,240 at 8% compounded<br> annually for 2 years

saw5 [17]

The answer is $1,446.33. 1,240 x 8% = $99.20 $1,240 + $99.20 = $1,339.20. $1,339.20 x 8% = $107.13 $1,339.20 + $107.13 = $1,446.33. Hope I could help! :D

4 0

3 years ago

The following lists the joint probabilities associated with smoking and lung disease among 60-to-65 year-old men. Has Lung Disea

Anna71 [15]

Answer:

4.11% probability that he has lung disease given that he does not smoke

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Does not smoke

Event B: Lung disease

Lung Disease/Nonsmoker 0.03

This means that $P(A \cap B) = 0.03$

Lung Disease/Nonsmoker 0.03

No Lung Disease/Nonsmoker 0.7

This means that $P(A) = 0.03 + 0.7 = 0.73$

What is the probability of the following event: He has lung disease given that he does not smoke?

$P(B|A) = \frac{0.03}{0.73} = 0.0411$

4.11% probability that he has lung disease given that he does not smoke

5 0

3 years ago