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2 years ago

What is 20 more than f

Mathematics

2 answers:

timurjin [86]2 years ago

6 0

This phrase can be written as 20 + f.

So, 20 + f is the answer.

Helga [31]2 years ago

6 0

20 + F is the answer
Hope this helps my friend :)

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Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and st

SashulF [63]

Answer:

0.7233

Step-by-step explanation:

We want to find the area between the z-scores z=-0.95 and z=1.25.

We first find the area to the left of each z-score, and subtract the smaller area from the bigger one.

For the area to the left of z=-0.95, we read -0.9 under 5 from the standard normal distribution table.

This gives P(z<-0.95)=0.1711

Similarly the area to the left of z=1.25 is

P(z<1.25)=0.8944

Now the area between the two z-scores is

P(-0.25<z<1.25)=0.8944-0.1711=0.7233

7 0

2 years ago

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

$336.04 < \mu < 443.96$

The margin of error will increase

The margin of error will decreases

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

$n \ \ \alpha \ \ \frac{1}{E^2 }$

So if the sample size increases the margin of error decrease

The sample proportion is mathematically represented as

$\r p = \frac{210}{500}$

$\r p = 0.42$

Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

=> $E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }$

=> $E = 0.0093$

The 99% confidence interval is

$\r p - E < p < \r p + E$

$0.42 - 0.0093 < p < 0.42 + 0.0093$

$0.4107 < p < 0.4293$

4 0

3 years ago

If x = 7+3 root 5 by 7 - 3 root 5 , find the value of x^2 + 1 by x^2

Vesnalui [34]

Answer:

6 because why not

Step-by-step explanation:

6 0

2 years ago

A plane flies from Houston to New York City in 4 hours the distance I traveled was 1627 miles what is the average speed of the p

Nikolay [14]

1627 / 4 = 406.75 miles per hr

5 0

3 years ago

OUT OF 32 STUDENTS IN A CLASS, 5 SAID THEY RIDE THEIR BIKES TO SCHOOL. BASED ON THESE RESULTS, HOW MANY OF THE 800 STUDENTS IN

svet-max [94.6K]

Let, the total number of students in school that ride the bike to school be "x"
Now,
Using ratio and proportion, we get,
$\frac{5}{32} = \frac{x}{800}$

$\frac{5}{32}*800 = \frac{x}{800} *800$

$\frac{4000}{32} =x$

$125 =x$

$x=125$

So, out of 800 students, 125 ride their bike to school.

4 0

2 years ago