Pls help me with this question.

5. The point (-2, -3) is rotated 90 degrees counterclockwise using center (0, 0).

SSSSS [86.1K]

B. (−3, 2)

I think

so plz have a good rest of ur day

7 0

3 years ago

Read 2 more answers

Ricky can ride 17 km on his bike in the same length of time ha can walk 9 km.if his riding speed is 4 kph faster than his walkin

aivan3 [116]

Distance=speed times time
if they take the same time, we cal the time , t

b=bike speed
w=walking speed

bikedistnace=17=bt
walkdistance=9=wt

b is 4 more than w
b=4+w

we have
17=bt
9=wt
b=4w

ok so
multiply first equation by 9 and 2nd by 17

153=9bt
153=17wt
set equal
9bt=17wt
divide both sides by t
9b=17w
sub b=4+w for b
9(4+w)=17w
distribute
36+9w=17w
minus 9w both sides
36=8w
divide both sides by 8
4.5=w

he walks 4.5kph

5 0

3 years ago

Tony sees an outfit that he

REY [17]

Answer:

He need 345 $

Step-by-step explanation:

Data :

Shirt = 50 $

Pant = 75 $

Shoes = 375 $

Now add them

50 + 75 + 375 = 500 $ value 1

He has 155 $ value 2

Subtrate value 2 from value 1

500 - 155 = 345 $

7 0

2 years ago

EFV and EDW are straight lines. Find the value of x and of y.

Makovka662 [10]

Answers:

x = 72

y = 83

============================================================

Explanation:

Angle VFG is 50 degrees. The angle adjacent to this is angle EFG which is 180-50 = 130 degrees.

Angle HDW is 77 degrees. The supplementary angle adjacent to this is 180-77 = 103 degrees which is angle EDH.

Pentagon EFGHD has the following five interior angles

E = x
F = 130
G = 170
H = 65
D = 103

Note that angles F = 130 and D = 103 were angles EFG and EDH we calculated earlier.

For any pentagon, the interior angles always add to 180(n-2) = 180(5-2) = 180*3 = 540 degrees.

This means,

E+F+G+H+D = 540

x+130+170+65+103 = 540

x+468 = 540

x = 72

---------------------------------------

Now focus your attention on triangle THS

We see that the interior angles are

T = y
H = 65
S = 32

The angle H is 65 degrees because it's paired with the other 65 degree angle shown. They are vertical angles.

For any triangle, the angles always add to 180

T+H+S = 180

y+65+32 = 180

y+97 = 180

y = 180-97

y = 83

7 0

2 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

2 years ago