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aniked [119]
3 years ago
15

Select the best answer for the question.

Mathematics
1 answer:
Tanzania [10]3 years ago
3 0

Answer:

A. 1 hour and 16 minutes

Step-by-step explanation:

There are 250 mL of D5W infusing at 33 gtt/min on IV tubing calibrated at 10 gtt/mL.  Calculate the infusion time.

select "No IV pump"

volume = 250 mL

rate = 33 gtt/min

calibration = 10 gtt/mL

Actual formula:

250 /( 33 gtt/min

10x  60)= 1.26 Hours

0.26 x 60 = 16 minutes

So 1.26 Hours = 1 Hour & 16 minutes

hope this will help you

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43 is an odd number.
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3 years ago
q(x)= x 2 −6x+9 x 2 −8x+15 ​ q, left parenthesis, x, right parenthesis, equals, start fraction, x, squared, minus, 8, x, plus, 1
AURORKA [14]

According to the theory of <em>rational</em> functions, there are no <em>vertical</em> asymptotes at the <em>rational</em> function evaluated at x = 3.

<h3>What is the behavior of a functions close to one its vertical asymptotes?</h3>

Herein we know that the <em>rational</em> function is q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15), there are <em>vertical</em> asymptotes for values of x such that the denominator becomes zero. First, we factor both numerator and denominator of the equation to see <em>evitable</em> and <em>non-evitable</em> discontinuities:

q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15)

q(x) = [(x - 3)²] / [(x - 3) · (x - 5)]

q(x) = (x - 3) / (x - 5)

There are one <em>evitable</em> discontinuity and one <em>non-evitable</em> discontinuity. According to the theory of <em>rational</em> functions, there are no <em>vertical</em> asymptotes at the <em>rational</em> function evaluated at x = 3.

To learn more on rational functions: brainly.com/question/27914791

#SPJ1

8 0
1 year ago
A concert earned $3,745 in ticket sales. One ticket to the concert cost $35.
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Answer:

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Step-by-step explanation:

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