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True [87]
3 years ago
9

A. 35 B. 96 C. 51 D. 80

Mathematics
2 answers:
Marysya12 [62]3 years ago
3 0
I think it would be A
slamgirl [31]3 years ago
3 0

Answer:

Its D

Step-by-step explanation:

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Suppose Set A contains 19 elements and Set B contains 69 elements. If the total number elements
balu736 [363]

B u A = 48

B = 45

The part of set B not included in A is B - A∩B  = 45 - 7 = 38

Since B u A = 48,  A must have 48-38 = 10 elements (3 exclusive of B, 7 shared with B).

------

Alternatively, the inclusion-exclusion principle may be used:   A  +  B  - (A ∩ B) = A u B  

  A + 45 - 7 = 48

  A  = 48 - 45 + 7  

   A = 10

NOTE that I'm using A and B  to indicate the number of elements in each set, respectively.

More formally, one would write |A|  and |B| to indicate the cardinality (number of elements) of the set.

6 0
3 years ago
2.5 gallons = 1 minute
postnew [5]

Answer:

how many days?

Step-by-step explanation:

My answer would be 25 gallons

3 0
3 years ago
Read 2 more answers
Use the following scenario to answer the question below: A remote control car races straight down the street at 26 miles per hou
Arte-miy333 [17]
Begin making a chart of each car per hour. answer: 2hours
7 0
4 years ago
Ments
maw [93]

The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

<h3>How to find a sector area, and arc length?</h3>

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

A = \frac{\theta}{360} * \pi r^2 --- sector area

L = \frac{\theta}{360} * 2\pi r ---- arc length

<h3>How to find the given sector area, and arc length?</h3>

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

A = \frac{\theta}{360} * \pi r^2

So, we have:

A = \frac{160}{360} * \frac{22}{7} * 5^2

Evaluate

A = 34.92

The arc length is:

L = \frac{\theta}{360} * 2\pi r

So, we have:

L = \frac{160}{360} * 2 * \frac{22}{7} * 5

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

Read more about sector area and arc length at:

brainly.com/question/2005046

#SPJ1

8 0
2 years ago
Of the 75 boys in athletics, 6 boys wanted to play tennis. What percent of the boys in athletics wanted to play tennis?
Arlecino [84]

Answer:

4.5%

Step-by-step explanation:

I am pretty sure that 6 percent of 75 is 4.5..

I hope that this helps u

8 0
4 years ago
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