we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
How to find the dimensions of the large rectangle?
First, we know that the large rectangle is the smaller rectangle rescaled, with a scale factor k = 4.
This means that each dimension of the smaller rectangle must be multiplied by 4 to get the correspondent dimension on the larger rectangle.
The dimensions of the smaller rectangle are:
l₁ = 12in
w₁ = 8in
Then the correspondent dimensions of the large rectangle are:
l₂ = 4*12in = 48 in
w₂= 4*8in = 32in
Now, the area of the large rectangle is given by the product between the two dimensions, we will get:
A₂ = 48in*32in = 1,536 in^2
Then, we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
If you want to learn more about rectangles:
brainly.com/question/17297081
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Answer:
x = 7
Step-by-step explanation:
The point-slope equation of the line is ...
y -(-13) = -3(x -3)
Substituting -25 for y, we can solve for x:
-25 +13 = -3x +9
-21 = -3x . . . . add -9
7 = x . . . . . . . divide by -3
Answer:
6.5 inches
Step-by-step explanation:
diameter=radius ×2
radius= diameter÷2
Diameter=13
13÷2=6.5
ANSWER: no
EXPLAIN: because a proportional relationship graph would have a straight line running through the origin
