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sweet-ann [11.9K]
3 years ago
6

What volume, in milliliters, of water is needed to make an 8.40 M solution of HCl acid using 180. grams of HCI ?

Chemistry
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

0 587 mL

Explanation:

First we convert 180 grams of HCl into moles, using its molar mass:

  • 180 g ÷ 36.46 g/mol = 4.94 mol HCl

Now we can <u>use the number of moles and the given concentration to calculate the required volume</u>, applying the <em>definition of molarity</em>:

  • Molarity = moles / liters
  • Liters = Moles / molarity
  • 4.94 mol / 8.40 M = 0.588 L

Finally we <u>convert liters into milliliters</u>:

  • 0.588 L * 1000 = 588 mL

The closest answer is option C, 587 mL.

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