Question

What volume, in milliliters, of water is needed to make an 8.40 M solution of HCl acid using 180. grams of HCI ?

Answer 1

Answer:

0 587 mL

Explanation:

First we convert 180 grams of HCl into moles, using its molar mass:

• 180 g ÷ 36.46 g/mol = 4.94 mol HCl

Now we can use the number of moles and the given concentration to calculate the required volume, applying the definition of molarity:

• Molarity = moles / liters

• Liters = Moles / molarity

• 4.94 mol / 8.40 M = 0.588 L

Finally we convert liters into milliliters:

• 0.588 L * 1000 = 588 mL

The closest answer is option C, 587 mL.