A sample of helium has a volume of 5 liters and a pressure of 699 mmHg. If the final volume is 5.7 Liters, its final temperature 303 K, and the final pressure 800 mmHg, what was the initial temperature of helium?
1 answer:
Answer:
The initial temperature of helium was T1 = 232.23 K
Explanation:
Given data:
Initial volume V1 = 5 L
Initial pressure P1 = 699 mmHg
Final pressure P2 = 800 mmHg
Final volume V2 = 5.7 L
Final temperature T2= 303 K
Initial temperature T1 = ?
Solution:
Formula:
P1V1/T1 = P2V2/T2
T1 = T2 × P1V1/P2V2
T1 = 303 K × 699 mmHg × 5 L / 800 mmHg × 5.7 L
T1 = 1058985/ 4560
T1 = 232.23 K
initial temperature of helium was 232.23 k.
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