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VashaNatasha [74]
3 years ago
15

Given the following matrix, where a is constant, find the indicated matrix:

Mathematics
1 answer:
Serga [27]3 years ago
8 0

I see this problem as asking, "given the matrix E, find E^3".

We can do this directly by computing the matrix product E^3=EEE.

E=\begin{bmatrix}2a&0&-a\\0&1&2\\-3&a&0\end{bmatrix}

\implies E^2=\begin{bmatrix}2a&0&-a\\0&1&2\\-3&a&0\end{bmatrix}\begin{bmatrix}2a&0&-a\\0&1&2\\-3&a&0\end{bmatrix}=\begin{bmatrix}4a^2+3a&-a^2&-2a^2\\-6&2a+1&2\\-6a&a&5a\end{bmatrix}

\implies E^3=\begin{bmatrix}4a^2+3a&-a^2&-2a^2\\-6&2a+1&2\\-6a&a&5a\end{bmatrix}\begin{bmatrix}2a&0&-a\\0&1&2\\-3&a&0\end{bmatrix}=\begin{bmatrix}8a^3+12a^2&-2a^3-a^2&-4a^3-5a^2\\-12a-6&4a+1&10a+2\\-12a^2-15a&5a^2+a&6a^2+2a\end{bmatrix}

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Thanks guys for the help. This one and one more and I’m done!
Karolina [17]

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Step-by-step explanation:

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8 0
3 years ago
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A quadratic function has its vertex at the point (- 3, 8) . The function passes through the point (0, 0) . When written in verte
SIZIF [17.4K]

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Step-by-step explanation:

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amm1812
9:1 because you divide both sides by 8. Hope this helps :)
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